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lys-0071 [83]
3 years ago
5

If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pre

ssure was 760.0 mm HG?
Chemistry
1 answer:
mario62 [17]3 years ago
5 0

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

\frac{p1}{t1}  =  \frac{p2}{t2}

p1 = 760 mmHg

t1 = 343 K

t2=283.15 K

p2 = p1 \times  \frac{t2}{t1}

p2 = 760 \times  \frac{283.15}{343.0}

p2 = 627.4 \: mmhg

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