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erastova [34]
2 years ago
8

What do you divide the mass by to get the concentration of a solute?

Chemistry
1 answer:
aliya0001 [1]2 years ago
5 0

You divide by the mass of the solution.

Percent by mass is the mass of the solute divided by the mass of the solution, multiplied by 100.

Example:

You dissolve a 4.00 g sugar cube in 350 mL of tea at 80 °C. The density of water at 80 °C is 0.975 g/mL. What is the percent by mass of sugar in the solution?

Solution

Step 1 — Determine mass of the solute.

The solute is the sugar cube. Mass of solute = 4.00 g.

Step 2 — Determine mass of solvent.

The solvent is the 80 °C water. Use the density of the water to find the mass.

mass of solvent = 350 mL ×

0.975

g

1

mL

= 341 g

Step 3— Determine the total mass of the solution

mass of solution = mass of solute + mass of solvent = 4.00 g + 341 g = 345 g

Step 4 — Determine percent composition by mass of the sugar solution.

% by mass =

mass of solute

mass of solution

× 100 % =

4.00

g

345

g

× 100 % = 1.159 %

The percent composition by mass of the sugar solution is 1.159 %.

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What is the percentage strength (w/w) of a solution made by dissolving 62.5 g of potassium chloride in 187.5 ml of water?
kiruha [24]

Percent strength (% w/w) of a solution is defined as the amount of solute present in 100 g of the solution.

Given data:

Mass of the solute, potassium chloride = 62.5 g

Volume of water (solution) = 187.5 ml

We know that the density of water = 1 g/ml

Therefore, the mass corresponding to the given volume of water

= 187.5 ml * 1 g/1 ml = 187.5 g

We have a solution of 62.5 g of potassium chloride in 187.5 g water

Therefore, amount of solute in 100 g of water= 62.5 * 100/187.5 = 33.33

The percentage strength = 33.33 %

8 0
3 years ago
Which elements above will form cations? List them below.
cricket20 [7]

Answer:

Halogens always form anions, alkali metals and alkaline earth metals always form cations. Most other metals form cations (e.g. iron, silver, nickel), whilst most other nonmetals typically form anions (e.g. oxygen, carbon, sulfur).

Explanation:

Examples: Sodium (Na+), Iron (Fe2+), Ammonium (NH4

7 0
3 years ago
Balanced equation of magnesium metal and hydrochloric acid
Setler79 [48]

The balanced chemical equation is,

2Mg+2HCl→2MgCl+H2↑

6 0
3 years ago
A chemist adds of a calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has
Elanso [62]

The given question is incomplete. The complete question is:

A chemist adds 0.85 L of a 0.0050M calcium sulfate to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask. Round your answer to significant digits.

Answer: The mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of CaSO_4 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{136g/mol}

Now put all the given values in the formula of molarity, we get

0.0050=\frac{x}{136\times 0.85}

x=0.58 g

Therefore, the mass in grams of calcium sulfate the chemist has added to the flask is 0.58 g

7 0
3 years ago
what volume of 1.75 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3 ?
Evgesh-ka [11]

The balance chemical equation is :

2HCL + Na2CO3 -----> 2NaCl + H2O + CO2

According to Question,

Given,

Molarity of HCL = 1.75 m

Sodium Carbonate (Na2CO3) = 0.100 m

For finding out the molarity,

c = n solute / Vsolution  => n = c.Vsolution

nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3

0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3

= 0.150 moles of  H3O^+

As we have already know the molarity of HCL , we easily calculate what volumes by many moles.

c = nsolute / Vsolution => Vsolution = nsolute / c

VH3O^+ = 0.150 moles / 1.75 mol L^-1 =  0.0857 L

To know more about Molarity here :

brainly.com/question/8732513?referrer=searchResults

#SPJ4

6 0
1 year ago
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