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ivanzaharov [21]
2 years ago
6

Suppose we consider the system of the three capacitors as a single "equivalent" capacitor. Given the charges of the three indivi

dual capacitors calculated in the previous part, find the total charge Qtot for this equivalent capacitor.
Physics
1 answer:
emmainna [20.7K]2 years ago
8 0

Answer:

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Explanation:

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You might be interested in
A(n) 0.2 kg object is swung in a vertical circular path on a string 0.1 m long. The acceleration of gravity is 9.8 m/s2 . If a c
Leya [2.2K]

Answer:

T=83.37N

Explanation:

Since the object is under a circular motion, according to Newton's second law, when the object is at the top of the circle we have:

\sum F_y: T-mg=F_c

Where F_c is the centripetal force and is given by:

F_c=ma_c=m\frac{v^2}{r}

Replacing and solving for T:

T=m\frac{v^2}{r}+mg\\T=0.2kg\frac{(6.38\frac{m}{s})^2}{0.1m}+0.2kg(9.8\frac{m}{s^2})\\T=83.37N

8 0
3 years ago
does increasing the frequency of a wave also increase its wavelength if not how are these quantities related​
Aleks [24]

Answer: Increasing the frequency does not increase the wavelength. They are inversely related.

Explanation:

As wavelength increases, frequency decreases. If you look at a transverse wave and it has a long wavelength, there only a few waves produce. Which means there is less frequency produced. So as wavelength increases, frequency decreases. The other way around can work to. As frequency increases, wavelength decreases. They are inversely related.

8 0
3 years ago
A 1000-kilogram car traveling due east at 15 meters per second hit from behind and receives a forward impulse of 6000 newton-sec
strojnjashka [21]

The change in momentum of the car is 6000 kg m/s

Explanation:

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on the object, therefore:

\Delta p = I

where

\Delta p is the change in momentum

I is the impulse exerted

For the car in this problem, the impulse received is

I = 6000 kg m/s (in the forward direction)

Therefore, the change in momentum of the car is equal to this value:

\Delta p = I = 6000 kg m/s (in the forward direction)

We can also calculate what is the new momentum of the car. In fact, the initial momentum is

p_i = mu = (1000 kg)(15 m/s)=15,000 kg m/s

And  so, the new momentum is

p_f = p_i + \Delta p = 15,000 + 6,000 = 21,000 kg m/s

Learn more about impulse and momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0
2 years ago
If a car was moving at a speed of 25mph for 6 hours, how far would the car travel?​
Anestetic [448]

Answer:

150 miles

Explanation:

25mph x 6hrs = 150miles

7 0
2 years ago
An archer pulls a bowstring back a distance of 20 cm with an average force of 75 N. The arrow has a mass of 20.0 g. When he rele
Masja [62]

To solve this problem we will apply the concepts related to the work theorem for which it is defined as the product of Force and distance. In turn, we will use the energy conservation theorem for which the applied work must be equivalent to the total kinetic energy on the body.

The work is defined as

W = Fd

Here,

F = Force

d = Displacement

Replacing with our values we have that

W = 75*0.2

W = 15J

Now by conservation of energy,

W = KE

W = \frac{1}{2}mv^2

15 = \frac{1}{2} (20*10^{-3}kg)(v^2)

Solving for v,

v = 10\sqrt{15}

v = 38.72 \approx 39

Therefore the correct answer is D.

8 0
3 years ago
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