Suppose we consider the system of the three capacitors as a single "equivalent" capacitor. Given the charges of the three indivi
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Answer :
556.59 m/s.
Explanation:
Given that,
An airplane is traveling at an altitude of 15,490 meters.
A box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.
The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :
Put u = 0 and a = g
So, when it hits the ground its velocity is 556.59 m/s.
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
So the total charge on the surface of the sphere is, using the charge density
:
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
is the point charge
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
So the total charge on the surface of the sphere is, using the charge density
The electrostatic force between the sphere and the point charge is:
where
ke is the Coulomb's constant
Q is the charge on the sphere
r is their separation
Re-arranging the equation, we can find the separation between the sphere and the point charge:
Given
Initial velocity:
36 ft/s
Initial height:
0 ft
Vertical motion model:
h(t) = -16t^2 + ut + s
v = initial velocity
s = is the height
Procedure
We are going to use the model provided for the vertical motion.
We know that at the maximum height the final velocity is 0.
Then we will use the following expression to calculate the maximum height:
Now for time:
Solving for t,
The total time the kangaroo takes in the air is 2.3s.