Answer:
The altitude of geostationary satellite is 
Explanation:
Given that,
Radius of moon's orbit 
Time period 
We need to calculate the orbital radius of geostationary satellite is
Using formula of time period


Where, G = gravitational constant
M = Mass of earth
T = time period of geostationary satellite orbit
Put the value in to the formula


We need to calculate the altitude of geostationary satellite
Using formula of altitude

Where, R = radius of earth
a = radius of geostationary satellite
Put the value into the formula



Hence, The altitude of geostationary satellite is 
Answer: The pressure in a liquid dec reaches with depth. F
The pressure in a liquid increases with depth.
The upthrust on an object is larger when it is deeper in a pool. 7
The bottom of a dam is thinner than the top of a dam. F
The bottom of a dam is thicker than the top of a dam.
The pressure is bigger at the bottom of a lake because of the weight of water above it. 7
I think these are the answers.
I'm not sure if a figure or some choices go along with this, but the closer to the sea floor the diver is, the lower the potential energy