Question

A 650.0 mL solution contains 125 grams of glucose (C6H1206). If the molar mass of CGH1206 IS 180.16 g/mol, what is the molarity of this solution?
a) 0.0106 M CH1206
b) 0.0195 M C6H1206
c) 1.07 M C6H1206
d) 1.92 M C6H1206

Answer 1

Answer:

c) 1.07 M C6H1206

Explanation:

Molarity is the molar concentration of a solution, which is glucose in this case. It can be calculated using the following formula:

Molarity (M) = number of moles (n) ÷ volume (V)

Using mole = mass/molar mass, to calculate the number of moles of glucose in the solution, where mass = 125grams and MM = 180.16g/mol

mole = 125/180.16

mole = 0.694mol

Volume = 650.0 mL = 650/1000 = 0.650 L

Molarity = n/V

Molarity = 0.694/0.650

Molarity = 1.07 M