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3 years ago

10

Which two types of potential energies would be types of mechanical energies? electrical and kinetic nuclear and chemical radiant

and thermal elastic and gravitational

2 answers:

katrin [286]3 years ago

6 0

Answer:

I can indeed confirm it is D.

Explanation: e d g e n u i t y

GuDViN [60]3 years ago

5 0

Answer:

D i think

Explanation:

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Ancient Greek philosophers were the first to discuss atoms and matter. This became known in time as____________. Atomic theory s

Vedmedyk [2.9K]

Answer:

atoms,

Explanation:

sorry don't know the second answer

6 0

3 years ago

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

spin [16.1K]

Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.

3 0

4 years ago

An electric dipole having dipole moment of magnitude p is placed in a uniform electric field having magnitude E. What is the mag

Daniel [21]

Answer:

Explanation:

The formula for the potential energy of a dipole placed in an electric field is given by

U = - pE Cos θ

where, θ is the angle between dipole moment and the electric field vector.

For θ = 0°,

initial potential energy, Ui = - pE

For θ = 180°,

final potential energy, Uf = - pE Cos 180 = pE

Change in potential energy

ΔU = Uf - Ui

ΔU = pE - (-pE)

ΔU = 2pE

5 0

4 years ago

Which two changes would decrease the electric force between two charged

My name is Ann [436]

Answer:

Decrease the charge of one of the particles

3 0

3 years ago

Consider a rocket that is in deep space and at rest relative to an inertial reference frame. The rocket's engine is to be fired

ValentinkaMS [17]

Answer:

$\frac{m_i}{m_f}=2.7182$

$\frac{m_i}{m_f}=1096.633$

Explanation:

$m_i$ = Initial mass of rocket

$m_f$ = Final mass of rocket

u = Initial velocity

$v_r$ = Relative velocity

v = Velocity

From the rocket equation

$v=u+v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v}}=e^1\\\Rightarrow \frac{m_i}{m_f}=2.7182$

$\frac{m_i}{m_f}=2.7182$

when $v=7v_r$

$v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{7v_r}{v_r}}=e^7\\\Rightarrow \frac{m_i}{m_f}=1096.633$

$\frac{m_i}{m_f}=1096.633$

6 0

3 years ago