Answer:
La intensidad del campo eléctrico es 70312.5 
.
Explanation:
La perturbación que crea en torno a ella una carga eléctrica se representa mediante un vector denominado campo eléctrico.
Se dice que un campo eléctrico es uniforme en una región del espacio cuando la intensidad de dicho campo eléctrico es el mismo en todos los puntos de dicha región.
El campo eléctrico E creado por la carga puntual q en un punto cualquiera P se define como:
donde q es la carga creadora del campo, k es la constante electrostática y r es la distancia desde la carga fuente al punto P.
En este caso, los datos son:
- k= 9*10⁹
- q= 5*10⁻⁶ C
- r= 0.8 m
Reemplazando:
Resolviendo:
E= 70312.5
<em><u>La intensidad del campo eléctrico es 70312.5 </u></em><em><u>.</u></em>
The object will continue moving in a straight line at constant speed.
a. 0.5 T
- The amplitude A of a simple harmonic motion is the maximum displacement of the system with respect to the equilibrium position
- The period T is the time the system takes to complete one oscillation
During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.
So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion
and solving for t we find
b. 1.25T
Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that
- the mass takes a time of 1 T to cover a distance of 4A
we can set the following proportion:
And by solving for t, we find
Answer:
yes
Explanation:
objects with constant velocity also have zero net external force. this means the forces on the object are balanced. this mean they are in equilibrium
