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3 years ago

10

The charges that are free to move in a metallic conducting wire and that are responsible for the flow of electric current are

1 answer:

Anna007 [38]3 years ago

6 0

Answer:Negatively charged particle called Free Electrons

Explanation:

Current is the flow of charged particles called Free electrons. Electrons are free to move from one atom to another and we call them a sea of de-localized electrons. In absence of any externally applied emf, these electrons are randomly moving but with the onset of emf, these electrons flow in a particular direction.

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A force of 10N is required to stretch a spring from 20cm to 25cm. What is the spring constant in N/m2 Be careful of unit

kupik [55]

Answer:

C) 40 N/m

Explanation:

If we ASSUME that the spring is un-stretched at the zero cm position

k = F/Δx = 10/0.25 = 40 N/m

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3 years ago

A 2kg water balloon is flying at a rate of 4m/s^2. With what force will it hit its target?

blondinia [14]

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

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3 years ago

9. The UL panel on the bottom of an electric toaster oven indicates that it operates at 1500 W on a 110 V circuit. Determine the

BigorU [14]

Answer:

8.067 ohms

Explanation:

The relationship between voltage, resistance, and power is ...

P = V²/R

so ...

R = V²/P = 110²/1500 = 8 1/15

R ≈ 8.067 . . . ohms

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3 years ago

The brightness of a star depends on its (color, composition of atmosphere, or distance from earth), and stars that are closer lo

PolarNik [594]

Answer:

Distance, Brighter

Explanation:

Think of a flash light, one close and one far which is brighter and which is dimmer.

Hope this is what your teacher put as the answer!

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3 years ago

Read 2 more answers

A Chevrolet Corvette convertible can brake to a stop from a speed of 60.0 mi/h in a distance of 123 ft on a level roadway. What

Digiron [165]

Answer:

83.1946504051 m

Explanation:

u = Initial velocity = $60\ mph=\dfrac{60\times 1609.34}{3600}=26.82233\ m/s$

s = Displacement = $123\ ft=\dfrac{123}{3.281}=37.4885705578\ m$

$\theta$ = Angle = $26^{\circ}$

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{0^2-26.82233^2}{2\times 37.4885705578}\\\Rightarrow a=-9.5954230306\ m/s^2$

Coefficient of friction

$\mu=-\dfrac{a}{g}\\\Rightarrow \mu=\dfrac{9.5954230306}{9.81}\\\Rightarrow \mu=0.978126710561$

$mg sin\theta - u mg cos\theta = ma\\\Rightarrow a=9.81(sin26-0.978126710561cos26)\\\Rightarrow a=-4.32382\ m/s^2$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-26.82233^2}{2\times -4.32382}\\\Rightarrow s=83.1946504051\ m$

The stopping distance is 83.1946504051 m

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4 years ago