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3 years ago

11

A plane flying at an altitude of 33,000 feet at a speed of 630 miles per hour releases a bomb. Find the tangential and normal co

mponents of acceleration acting on the bomb.

1 answer:

Galina-37 [17]3 years ago

8 0

Ignoring air resistance . . .

After the bomb is released, tangential (horizontal) acceleration is zero,, normal (vertical) acceleration is 9.8 m/s^2 down (gravity).

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Two skaters collide and grab on to each other on frictionless ice. One of them, of mass 66.0 kg , is moving to the right at 2.00

ivann1987 [24]

Answer:

The velocity of skaters after collision is 0.55 m/s and they are moving to the left

Explanation:

Consider m₁ and m₂ are the masses of two skaters and their initial velocity be v₁ and v₂ respectively.

Consider the velocity along right direction as positive while negative for left direction.

According to the problem,

Mass of first skater, m₁ = 66.0 kg

Mass of second skater, m₂ = 75.0 kg

Velocity of first skater, v₁ = + 2.00 m/s

Velocity of second skater, v₂ = -2.80 m/s

Since, the two skaters grab each other after collision. Hence, they are moving with same final velocity v.

Applying conservation of linear momentum,

Momentum before collision = Momentum after collision

m₁v₁ + m₂v₂ = (m₁+m₂)v

Substitute the suitable values in the above equation.

66 x 2 - 75 x 2.8 = (66 + 75 )v

$v= \frac{-78}{141}$

v = -0.55 m/s

The negative sign denotes that both the skaters are moving in the left direction.

6 0

4 years ago

How much energy (in kj) do 3.0 moles of photons, all with a wavelength of 670 nm, contain? how much energy (in kj) do 3.0 moles

Kisachek [45]

1 mole of photons contain $6.023 \cdot 10^{23}$ photons (Avogadro number). This means that 3.0 moles of photons contain
$N=3\cdot 6.023 \cdot 10^{23} =1.81 \cdot 10^{24}$ photons.

The wavelength of the light in the problem is $\lambda=670 nm=670\cdot 10^{-9}m$ , so the frequency is
$f= \frac{c}{\lambda}= \frac{3\cdot 10^8 m/s}{670 \cdot 10^{-9}m}=4.48 \cdot 10^{14}Hz$

The energy carried by a single photon is
$E=hf$
where $h=6.62 \cdot 10^{-34}Js$ is the Planck constant, while f is the frequency. Since this is the energy carried by a single photon, the energy carried by 3.0 moles of photons will be the energy of the single photon multiplied by the total number of photons:
$E=Nhf=(1.81 \cdot 10^{24})(6.62 \cdot 10^{-34}Js)(4.48 \cdot 10^{14}Hz )=5.36 \cdot 10^5 J$
which corresponds to E=536 kJ.

4 0

3 years ago

The physical and chemical properties of a substance are used to identify the substance and to see how it will behave in the pres

pentagon [3]

Im going to guess on this one, and say that it is chemical.

8 0

3 years ago

Read 2 more answers

Discuss 4 way a scienicst can.reduce bias

Yanka [14]

Make sure to thank me

The answers are by:

Investigation
Sampling
Repetition
Blind Studies

7 0

4 years ago

Read 2 more answers

The statement that "the lowest energy configuration for an atom is the one having the maximum number of unpaired electrons allow

LUCKY_DIMON [66]

Answer:

Hund's rule

Explanation:

Hund's rule is defined as the rule whose first rule in the chemistry says that, for a given electronic configuration, the term which posses lowest energy has maximum multiplicity. The multiplicity is defined as the tem 2S+1, where S is the total spin angular momentum.

Therefore, the term which has lowest energy that term posses maximum number of S.

Hund's rule of maximum multiplicity: Electron present in same energy orbitals firstly they completed half orbit than start pairing.

Therefore, the energy of lowest configuration for an atom is the one having the maximum number of unpaired electron which is allowed by the Pauli principle in a particular set of degenerate orbit is called Hund's rule.

8 0

3 years ago

Read 2 more answers