Answer:
second-law efficiency = 62.42 %
Explanation:
given data
temperature T1 = 1200°C = 1473 K
temperature T2 = 20°C = 293 K
thermal efficiency η = 50 percent
solution
as we know that thermal efficiency of reversible heat engine between same temp reservoir
so here
efficiency ( reversible ) η1 = 1 - 
............1
efficiency ( reversible ) η1 = 1 - 
so efficiency ( reversible ) η1 = 0.801
so here second-law efficiency of this power plant is
second-law efficiency = 
second-law efficiency = 
second-law efficiency = 62.42 %
Answer:
4/5
Explanation:
She is not wearing white t-shirt on the first day so she is wearing the other 4 t-shirt
Answer:
No, they need to be somewhat flexible so that forces such as turbulance don't shear the wing off.
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<h3>What are online information?</h3>
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Answer:
Explanation:
solution:
from this below equation (1)
σ/2εo
...........(1)
we obtain:
