Answer:
1.2 atm
Explanation:
Given data
- Volume of the gas in the tank (V₁): 200.0 L
- Pressure of ethylene gas in the tank (P₁): ?
- Volume of the gas in the torch (V₂): 300 L
- Pressure of the gas in the torch (P₂): 0.8 atm
If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.
Answer:
millions of years sometimes even hundred of millions of years
Answer:
V = 48.5 L
Explanation:
Converting °C to K and kPa to atm
T = 25.0°C + 273.15 = 298.15 K
P = 61.3 kPa × (1 atm / 101.325 kPa) = 0.60498 atm
Calculating the volume of gas
V = nRT / P
V = (1.20 mol)(0.082057 L•atm/mol•K)(298.15 K) / 0.60498 atm
V = 48.5 L