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Bas_tet [7]
2 years ago
7

A truck moves 70 m east, then moves 120 m west, andfinally

Physics
1 answer:
SOVA2 [1]2 years ago
7 0

Answer:

40m (40m east)

Explanation:

The fist move is 70m east, and east is the positive direction so the truck initially is at +70m.

The second move is 120m to the west, since east is the positive direction, west must be the negative direction, this means the truck now is at:

+70m -120m = -50m

The third move is 90m to the east, again, this is the positive direction, so the new position is:

-50m + 90m = +40m.

The truck is at + 40m, so it ended up 40m away from its initial position and this is the resultant dispacement.

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Answer:

10628.87 J

Explanation:

We are given that

Force applied =F=5592 N

\theta=30.1^{\circ}

Displacement=D=3.79 m

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Work done=F\times displacement

The perpendicular component of force=FSin\theta=5592sin(30.1)=2804.45N

Work done =Fsin\theta\times D=2804.45\times 3.79=10628.87 J

Hence, the work done in sliding the piano up the plank at a slow constant rate=10628.87 J

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3 years ago
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I need help answering this question in the photo (middle)
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Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up.
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the car starts from a stop to travel 1100 meters in 14 seconds. it is clocked at 65 m/s at point k. find its average speed and a
inysia [295]

Answer:

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Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

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The velocity of the car at point k, v = 65 m/s

Using the II equation of motion,

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Substituting,

                           v = √(2 x 11.22 x 1100)

                              = 157.11 m/s

The average speed of the car,

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                        V = 74.04 m/s

Hence, the average velocity of the car is, V = 74.04 m/s

4 0
2 years ago
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