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2 years ago

A truck moves 70 m east, then moves 120 m west, andfinally

Physics

1 answer:

SOVA2 [1]2 years ago

7 0

Answer:

40m (40m east)

Explanation:

The fist move is 70m east, and east is the positive direction so the truck initially is at +70m.

The second move is 120m to the west, since east is the positive direction, west must be the negative direction, this means the truck now is at:

$+70m -120m = -50m$

The third move is 90m to the east, again, this is the positive direction, so the new position is:

$-50m + 90m = +40m.$

The truck is at + 40m, so it ended up 40m away from its initial position and this is the resultant dispacement.

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A 5592 N piano is to be pushed up a(n) 3.79 m frictionless plank that makes an angle of 30.1 ◦ with the horizontal. Calculate th

otez555 [7]

Answer:

10628.87 J

Explanation:

We are given that

Force applied =F=5592 N

$\theta=30.1^{\circ}$

Displacement=D=3.79 m

We have to find the work done in sliding the piano up the plank at a slow constant rate.

Work done= $F\times displacement$

The perpendicular component of force= $FSin\theta=5592sin(30.1)=2804.45N$

Work done = $Fsin\theta\times D=2804.45\times 3.79=10628.87 J$

Hence, the work done in sliding the piano up the plank at a slow constant rate=10628.87 J

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3 years ago

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If an automobile engine delivers 42.0 hp of power, how much time will it take for the engine to do 6.20 â 105 j of work? (hint:

Elena L [17]

To be able to answer this item, we are to calculate the power that the machine could deliver from hp to kW.

(45 hp)(746 W/1 hp) = 33570 W

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3 years ago

I need help answering this question in the photo (middle)

GalinKa [24]

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3 years ago

Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up.

Neko [114]

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3 years ago

the car starts from a stop to travel 1100 meters in 14 seconds. it is clocked at 65 m/s at point k. find its average speed and a

inysia [295]

Answer:

The average velocity of the car is, V = 74.04 m/s

Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

The displacement of the ca, S = 1100 m

The time period of travel, t = 14 s

The velocity of the car at point k, v = 65 m/s

Using the II equation of motion,

S = ut + ½ at²

Substituting the given values,

1100 = 0 + ½ x a x 14²

a = 11.22 m/s²

Using the III equation of motion

v² = u² + 2 as

v = √(2as) (∵ u = 0)

Substituting,

v = √(2 x 11.22 x 1100)

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The average speed of the car,

$V=\frac{0+65+157.11}{3}$

V = 74.04 m/s

Hence, the average velocity of the car is, V = 74.04 m/s

4 0

2 years ago