Answer:
The C4+ ion has the smallest ionic radius
Explanation:
In the periodic table, the size of an atom increases on going downwards in a group.
On the other hand, in a period, size decreases on going from left to right
The size of cation is smaller than its parent atom.
Lithium-ion (Li+) is the most left so it has the biggest radius.
More to the right ( this means a smaller ionic radius) , we have Berylium-ion (Be2+).
More to the right, so smaller than Be2+, we have B3+
The ion the most to the right, we have C4+
The C4+ ion has the smallest ionic radius
Li+ > Be2+ > Be3+ > C4+
The balanced chemical reaction is:
Na2SO4 + Ba(OH)2 = 2NaOH +BaSO4
We are given the amount of the reactants to be used. These values will be the starting point of our calculations.
0.0820 mol/L Ba(OH)2 (2.27 L solution) = 0.18614 mol Ba(OH)2
0.0664 mol/L Na2SO4 (3.06 L solution) = 0.20318 mol Na2SO4
The limiting reactant is the Ba(OH)2. The amount for this compound will be used.
0.18614 mol Ba(OH)2 (1 mol BaSO4 / 1 mol Ba(OH)2 ) (233.43 g BaSO4 / 1 mol BaSO4)= 43.4507 g BaSO4
Answer:
from the ph given find the negative of log of concentrations of hydrogen and hydroxyl ions in acid and base respectively..then write tghe no. of moles of hydrogen and hydroxide ions
The chemical nature of Q sepharose which allows it to be used as an ion exchanger include the following: It is an insoluble matrix which is in form of micro beads. The bead are porous, which provides a large surface area within and outside them. This properties make it possible for Q sepharose to finely separate different organic molecules.<span />
The answer is 2Sb2S3 + 902 yields 2Sb2O3 + 6SO2
And the question os just asking you to find the simplest for of balancing for this equation
