Answer:
- <em>There are </em><u><em>4 moles</em></u><em> of chloride ions in 2 moles of calcium chloride.</em>
Explanation:
Start by writing the chemical formula of calcium chloride.
The suffix -ide in chloride means that chlorine is working as the ion Cl⁻, this is with oxidation state -1.
Calcium, being an alkaline earth metal, uses oxidation state +2, Ca²⁺
Then, two atoms of Cl are combined with one atom of calcium, because in this way each Cl atom will accept one electron from a Ca atom, which will donate its two valence electrons.
That is indicated in the chemical formula with subscripts: <u><em>CaCl₂</em></u>, meaning that each formula-unit of calcium chloride has 2 ions of chlorine and 1 ions of calcium, or twice the number of moles of chloride ion.
- 1 mol CaCl₂ : 1 mol Ca⁺ : 2 mol Cl⁻
⇒ 2 mol CaCl₂ : 2 mol Ca⁺ : 4 mol Cl⁻
Hence, there are 4 moles of chloride ions in 2 moles of calcium chloride.
Answer:
An F1 offspring could produce four types of gametes, RY, Ry, rY, and ry. The F2 generation supports the independent-assortment model and refutes the linkage model.
Explanation:
Answer:
it'll halve
Explanation:
the gas is compressed with twice the pressure. The volume will be halved.
im certain
all i know is that the formula for triangles is base times hight divided by two, so add in a number to replace the missing number, multiply it by 55 and divide the answer by two. hope this helps and i really hope you get it right! or that im right...
Solution :
The buffer is the one that contains weak acid (the 
is nearly equal to the required pH) and the salt of its conjugate base.
The values of the given weak acids are as follows :
HCOOH : = 3.744
HCN : = 9.21
Since the required pH is 5.03, the suitable buffer is the mixture of the acetic acid and the salt of its conjugate base.
Let suppose the volumes of 
and 
are x and y mL respectively.
So the total volume of the buffer is 1000 mL.
∴ x+ y = 1000 ................(1)
Writing the Henderson-Hasselbalch equation for the given buffer solution :
![$pH = pK_a + \log \ \frac{[CH_3COONa]}{[CH_3COOH]}$](https://tex.z-dn.net/?f=%24pH%20%3D%20pK_a%20%2B%20%5Clog%20%5C%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D%24)
.............(2)
y = 1.9 x
Substituting the values of y in equation (1), we get
x + 1.9 x = 1000
x = 345
Putting the value of x in (1), we get
345 + y = 1000
y = 655
Therefore the volume of is 345 mL and the volume of is 655 mL.
