Answer:
CH4
Explanation:
In solving this problem, we must remember that one mole of a compound contains Avogadro's number of elementary entities. These elementary entities include atoms, molecules, ions etc. Recall that one mole of a substance is the amount of substance that contains the same number of elementary entities as 12g of carbon-12. The Avogadro's number is 6.02 × 10^23.
Hence we can now say;
If 163 g of the compound contains 6.13 ×10^24 molecules
x g will contain 6.02 × 10^23 molecules
x= 163 × 6.02 × 10^23 / 6.13 × 10^24
x= 981.26 × 10^23/ 6.13 ×10^24
x= 160.1 × 10^-1 g
x= 16.01 g
x= 16 g(approximately)
16 g is the molecular mass of methane hence x must be methane (CH4)
Answer:
im pretty sure 2+
Explanation:
subtract the electrons from the protons
:<span> </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2
(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl
(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.
(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2
(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
Rate law is determined the rate of the slowest chemical reaction since it determine the rate of overall reaction . but this applies when the slowest step come before the fast step. For the equation above the fast step come before the slowest step. The rate law is therefore.
2NO to n2o2 (fast)
N2O2 +O2 -->2NO2(SLOW)
NO2+O2 ---> NO +O3(FAST)
rare law = k2(N2O2)(O2)
