We have an aqueous solution that contains 35% (by mass) of a hypothetical solute Z. The formula weight of the solute Z is 118 g/

Question

2 years ago

15

mol. The density of the solution is observed to be 1.4 g/mL. What is the molarity of Z in this solution

1 answer:

Allisa [31] · Answer 1 · 2022-08-11T02:35:24+03:00

6 0

Answer:

4.15 M

Explanation:

In order to find the molarity of a stock solution of Z, we use the formula;

Co = 10pd/M

where;

p = percentage by mass of Z

d = density of Z

M= molar mass of Z

Substituting values;

Co= 10 * 35 * 1.4/118

C0= 4.15 M