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2 years ago

The speed of light is 300,000,000 m/s, what is the frequency of an x-ray that has a wavelength of .1 m? ____Hz?

Physics

1 answer:

Fittoniya [83]2 years ago

8 0

Answer:

Explanation:

The speed of light is 300,000,000 m/s. Shat is the frequency of microwaves with a wavelength of 0.01 meter

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4. O/N 15/P11/Q11

anygoal [31]

Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

P = F/A

It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

0.30(0.40) = 0.12 m²

0.30(0.50) = 0.15 m²

0.40(0.50) = 0.20 m²

The pressure when the face with the largest area (0.20 m²) is down is

P = 900 / 0.20 = 4500 N/m² or 4500 Pa

the other possible pressures would be

900/0.15 = 6000 Pa

900/0.12 = 7500 Pa

which are both larger than our solution.

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3 years ago

Please use this screenshot in any way you can

miskamm [114]

Ball 1 Has uchanging motion because it continually goes up no matter what. Ball 2 has no motion. And ball 3 changing motion because it goes from not moving to moving. Hope this helps

7 0

3 years ago

Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is

liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position = < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack = < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

= [(-440*4) + (0*0) + (220*-2)]

= -1760 J - 440 J

= -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

= [(170*4) + (0*0) + (340*-2)]

= 680 J - 680 J

= 0

7 0

4 years ago

A current of 6.93 A 6.93 A in a long, straight wire produces a magnetic field of 4.15 μT 4.15 μT at a certain distance from the

natka813 [3]

Answer:

0.334 m

Explanation:

The magnetic field due to current in a straight thin wire, $B$ , is given by

$B = \dfrac{\mu_0 I}{2\pi R}$

where $\mu_0$ is the permeability of free spave with value $4\pi\times10^{-7}$ and $R$ is the distance from the wire.

$R = \dfrac{\mu_0 I}{2\pi B}$

Substituting the values from the question,

$R = \dfrac{4\pi\times10^{-7}\times 6.93}{2\pi\times 4.15\times 10^{-6}}$

$R = \dfrac{2\times10^{-1}\times6.93}{4.15} = 0.334 \text{ m}$

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4 years ago

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Which of the following is an example of a main sequence star

Westkost [7]

The star is the main sequence

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3 years ago

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