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Paul [167]
3 years ago
10

During ________________________, a new nuclear membrane forms around eachgroup of chromosomes.

Chemistry
1 answer:
Gre4nikov [31]3 years ago
8 0

Answer:

Telophase

Explanation:

I looked up the ending lol!hope  this helps

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How many moles of gaseous boron trifluoride, BF3, are contained in a 4.3410 L bulb at 788.0 K if the pressure is 1.220 atm What
gregori [183]

Answer:

n= 0.08186

{He}2s^2 2p^6

Explanation:

PV=nRT

n=PV/RT

n= (1.220 atm)(4.3410 L) / (0.0821 atm*L/mol*K)(788.0 K)

n=0.08186

As for the electron configuration:

Ne:

{He} 2s^2 2p^6

or long hang:

1s^2 2s^2 2p^6

5 0
3 years ago
Why is alloy stainless steel used instead of pure iron for the ball of pen of pure iron for a ball of pen
Anna [14]

Answer:

so it want get so hot

Explanation:

so you want get burned

7 0
4 years ago
2. Which test for iron(II) ions is conclusive ​
krok68 [10]

Answer:

please brainlist answer

Explanation:

The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.

5 0
3 years ago
Read 2 more answers
Question 10(Multiple Choice Worth 5 points)
jarptica [38.1K]

Answer:

O Generation of electricity

Explanation:

because the others dont make sense to me and tbh carbon is used everyway and everywhere

7 0
2 years ago
14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At
avanturin [10]

Answer:

Tungsten is used for this experiment

Explanation:

This is a Thermal - equilibrium situation. we can use the equation.

Loss of Heat of the Metal = Gain of Heat by the Water

                      -Q_{m}=+Q_{w}\\

                    Q = mΔTC_{p}

Q = heat

m = mass

ΔT = T₂ - T₁

T₂ = final temperature

T₁ = Initial temperature

Cp = Specific heat capacity

<u>Metal</u>

m = 83.8 g

T₂ = 50⁰C

T₁ = 600⁰C

Cp = x

<u>Water</u>

m = 75 g

T₂ = 50⁰C

T₁ = 30⁰C

Cp = 4.184 j.g⁻¹.⁰c⁻¹

               -Q_{m}=+Q_{w}\\

⇒ - 83.8 x x x (50 - 600) = 75 x 4.184 x (50 - 30)

⇒ x = \frac{6276}{46090} = 0.13 j.g⁻¹.⁰c⁻¹

We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹

So metal Tungsten used in this experiment

8 0
4 years ago
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