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Bad White [126]
3 years ago
8

In science class, the teacher was conducting an experiment to determine if blowing air causes water to evaporate faster then if

there is no blowing air. She used one dish of water that was placed in front of a fan and another dish of water that was placed in a still location, so there would be no air blowing around it.
What is the control in this experiment?
Chemistry
1 answer:
stepan [7]3 years ago
5 0

Answer:

The control in this experiment is the temperature and amount of water.

Explanation:

This is because for it to be a fair test the temperature and the amount of water need to be the same so they would both evaporate if there was no air being blown. Ask me if you would like me to elaborate on this.

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increases my factor of 10

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A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold me
DiKsa [7]

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.

m = 38.2 to 3 sig digs.

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Hope this answers the question.
5 0
3 years ago
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