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Ostrovityanka [42]
3 years ago
6

The bond angle for methane is the angle determined by two consecutive hydrogen atoms and the central carbon atom.

Chemistry
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

a. True

Explanation:

The bond angle for methane is the angle determined by two consecutive hydrogen atoms and the central carbon atom.

Methane, a tetrahedron has the structural formula:

                             H

                              |

                    H  -   C   -  H

                              |

                             H            Methane, CH4

The bond angle is the angle between the H-C-H atoms and is 109.5degrees.

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What are the products of RbNO2 + BaCO3? <br><br> Please help!
Anton [14]

Answer:

RbCO3 +BaNO2

Explanation:

7 0
3 years ago
What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = pKa? Ka = 1.8×10-5
Westkost [7]

Answer:

a) We have to add 0.9 mole NaOH to 1.0 L of 1.8 M HC2H3O2

b) We have to add 0.277 mole NaOH to 1.0 L of 1.8 M HC2H3O2

c) We have to add 1.16 mole NaOH to 1.0 L of 1.8 M HC2H3O2

Explanation:

a) <em>What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = pKa?</em>

<em />

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = pK = -log(1.8*10^-5) = 4.74

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

4.74 = 4.74 + log(A-/HA)

0 =  log(A-/HA)

A-/HA = 1

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 1

X =0.9

<u>We have to add 0.9 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

To control we can do the following equation:

4.74 = 4.74 + log(0.9/0.9) = 4.74

b)<em> What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 4.00?</em>

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = 4

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

4 = 4.74 + log(A-/HA)

-0.74 =  log(A-/HA)

A-/HA = 0.182

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 0.182

X =0.277

<u>We have to add 0.277 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

<u> </u>

To control we can do the following equation:

4 = 4.74 + log(0.277/1.523)

<em></em>

<em>c) What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 5.00</em>

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = 5

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

5 = 4.74 + log(A-/HA)

0.26 =  log(A-/HA)

A-/HA = 1.82

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 1.82

X =1.16

<u>We have to add 1.16 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

<u> </u>

To control we can do the following equation:

5 = 4.74 + log(1.16/0.64) = 5

3 0
4 years ago
What is the concentration in molarity of a solution that has 54.21g of calcium hydroxide dissolved in 560mL of water?
ra1l [238]
We know that Molarity = # mol/L

In the question, we are given grams - so we need to calculate the number of moles that we are dealing with. We can do this by first finding out what the molecular formula of calcium hydroxide is: Ca(OH)_{2

This means that we have 1 calcium and 2 hydroxides.

We can find the number of moles by taking the grams given divided by the molar mass of the molecule. We can find the molar mass of the molecule by taking each atomic mass of each atom (found on the periodic table) and adding them together:

Ca = 40.08g
O = 15.999g
H = 1.008g

We have 1 calcium, 2 oxygens, and 2 hydrogens. So let's add the atomic masses together:

40.08 + 2(15.999) + 2(1.008) = 74.094g

Now that we have the molar mass, we can find the number of moles due to already knowing the given amount in the question:

54.21g/74.09g = 0.73 moles of Ca(OH)_{2}

Now that we know the number of moles, we can solve for the molarity; The other part of the question gives us 560 mL of water - but this can quickly be converted to liters by moving the decimal to the left 3 places => 0.560 L

Knowing all of this information, we can plug it into the molarity equation:

Molarity = 0.73 mol/0.56 L
Molarity = 1.30

The molarity of the solution is 1.3 M.
4 0
3 years ago
25 POINTS TO ANSWER WHAT IS THE NAME OF WHITE BLOOD CELLS THAT FIGHT OFF INFECTIONS?
Inessa [10]
The name is <span>leukocytes or leucocytes.
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3 years ago
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alexandr402 [8]
I think it’s 63.84 or 64
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