Exercise is the answer hope i helped you
Answer:
The inductor contains
loops
Explanation:
From the question we are told that
The capacitance of the capacitor is 
The resonance frequency is 
The diameter is 
The of the air-core inductor is 
The permeability of free space is 
Generally the inductance of this air-core inductor is mathematically represented as

This inductance can also be mathematically represented as

Where
is the angular speed mathematically given as

So

Now equating the both formulas for inductance

making N the subject of the formula


Substituting value
loops
<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.
Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>
Answer:
28,800m/p second
Explanation:
Calculate the distance per second so, 400m/50 s= 8m/p second now knowing the speed/hour and knowing an hour has 3,600 seconds,multiply it by 8 then you will get 28,800m/p second, or 28.8km/h