Answer:
Process asset updates.
Explanation:
Quality assurance assessments, validated modifications, authenticated deliverables, performance at work indicators, configuration management, project management plan modifications, project document security patches, and organisational process asset updates are the key outputs of quality assurance.
Answer:
The correct word for the blank space is: public.
Explanation:
A public corporation has sold stock through an<em> Initial Public Offering </em>(IPO) to the public and that stock is currently traded on a <em>public stock exchange</em> or the <em>Over-The-Counter</em> (OTC) market. The ability to sell public shares is very important to these businesses as it provides them with a source of capital for investment.
Answer:
16.80% and 39.43%
Explanation:
The formula to compute the net profit margin is shown below:
Net profit margin = Net income ÷ Total revenues × 100
For Travel lite, the net profit margin is
= $1,080 ÷ $6,430 × 100
= 16.80%
And, for fare line, the net profit margin is
= $3,020 ÷ $7,660 × 100
= 39.43%
By dividing the net income or net profit by the total revenues we can get the net profit margin or we can say it is profit percentage that is earned by the company
It is always expressed in percentage
Answer:
Jan's Bakery and Tina Cookies
Total Average Cost for the merged firm
= ($300,000 + $75,000)/2
= $187,500
Explanation:
The total average cost for Jan's Bakery and Tina's Cookies is the average of their total operating costs. This is obtained by adding $300,000 to $75,000 and then dividing by 2.
Though, in practical terms, the presence of some synergies will cut some of the operating costs off, especially such costs as rent, advertising, and some other administrative costs. Some selling costs will also be eliminated when the merger goes through.
Answer:
The speed of the car is 67.77 m/s and it is moving away from the observer.
Explanation:
The apparent frequency is given as
![f' = f\dfrac{ [v - vo]}{ [v - vs]}](https://tex.z-dn.net/?f=f%27%20%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D)
Here
o is the observer
s is the source which is car
v is the speed of sound = 343 m/s
f = true frequency emitted by the car (when stationary)
f ' = 0.835 f
so
![f' = f\dfrac{ [v - vo]}{ [v - vs]}\\0.835 f= f\dfrac{ [v - vo]}{ [v - vs]}\\0.835 = \dfrac{ [343 - 0]}{ [343 - vs]}\\0.835=\frac{343}{343-x}\\x=-67.77 m/s](https://tex.z-dn.net/?f=f%27%20%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D%5C%5C0.835%20f%3D%20f%5Cdfrac%7B%20%5Bv%20-%20vo%5D%7D%7B%20%5Bv%20-%20vs%5D%7D%5C%5C0.835%20%3D%20%5Cdfrac%7B%20%5B343%20-%200%5D%7D%7B%20%5B343%20-%20vs%5D%7D%5C%5C0.835%3D%5Cfrac%7B343%7D%7B343-x%7D%5C%5Cx%3D-67.77%20m%2Fs)
The speed of the car is 67.77 m/s and it is moving away from the observer.
