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3 years ago

Solve for the missing angle. Round to the nearest hundredth. 18 ? 13 ? = degrees

Mathematics

1 answer:

skad [1K]3 years ago

8 0

Answer:

$\theta \:=43.76^{\circ \:\:}$

Step-by-step explanation:

The right triangle has the hypotenuse = 18

Let 'Ф' be the missing angle

we know that

cos Ф = adjacent/hypotenuse

Here,

The adjacent to Ф = 13

The hypotenuse = 18

cos Ф = adjacent/hypotenuse

$cos\:\theta \:=\frac{13}{18}$

$\theta \:=\cos ^{-1}\left(\frac{13}{18}\right)$

$=43.76^{\circ \:}$

Therefore, the missing angle is:

$\theta \:=43.76^{\circ \:\:}$

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Vedmedyk [2.9K]

Answer:

$P(0.26 \leq p \leq 0.43)=0.7204-0.0032=0.7172$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The population proportion have the following distribution

$p \sim N(p=0.4,\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.4(1-0.4)}{91}}=0.0514)$

And we can solve the problem using the z score on this case given by:

$z=\frac{p_o -p}{\sqrt{\frac{p(1-p)}{n}}}$

We are interested on this probability:

$P(0.26 \leq p \leq 0.43)$

And we can use the z score formula, and we got this:

$P(\frac{0.26 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}} \leq Z \leq \frac{0.43 -0.4}{\sqrt{\frac{0.4(1-0.4)}{91}}})$

$P(-2.726 \leq Z \leq 0.584)$

And we can find this probability like this:

$P(-2.726 \leq Z \leq 0.584)=P(Z$

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3 years ago

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OverLord2011 [107]

Answer:

True

Step-by-step explanation:

Just compare the numbers to the dots.

I hope this helps!

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3 years ago

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melisa1 [442]

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The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The <em>first, second and third terms </em>of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

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Afina-wow [57]

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