It is the graph where the two lines intersect, when they intersect there is a point where they connect, and that is your answer
 
        
                    
             
        
        
        
Answer:
-3.84
Step-by-step explanation:
 
        
             
        
        
        
Answer:
Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East
||Vel_jet_r|| =  465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added  (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph  East  -  50 sin (45) mph North
Vel _wind =  35.35 mph  East  -  35.35 mph North
This means that the resulting  velocity of the jet is equal to
Vel_jet_r =  (500 mph - 35.35 mph) North + 35.35 mph East 
Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| =  sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| =  465.993 mph
 
        
             
        
        
        
Answer:
The answerscan be calculated by doing the following steps; 
Step-by-step explanation:
 
        
             
        
        
        
An equation in standard form looks like Ax + By = C.
Let C = 80
Take it from here.