A gas mixture is made up of kr (21.7 g), o2 (7.18 g), and co2 (14.8 g). the mixture has a volume of 23.1 l at 59 °c. calculate t
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Answer:
The number of moles of KClO₃ reacted was 0,15 mol
Explanation:
For the reaction:
2KClO₃(s) → 2KCl(s) + 2O₂(g)
The only gas product is O₂.
Total pressure is the sum of vapor pressure of water with O₂ gas formed. Thus, pressure of O₂ is:
749mmHg - 23,8mmHg = 725,2mmHg
Using gas law:
PV/RT = n
Where:
P is pressure (725,2mmHg ≡ <em>0,9542atm</em>)
V is volume (<em>5,76L</em>)
R is gas constant (<em>0,082 atmL/molK</em>)
And T is temperature (25°C ≡ <em>298,15K</em>)
Replacing, number of moles of O₂ are <em>0,2248 moles</em>
As 2 moles of KClO₃ react with 3 moles of O₂ the moles of KClO₃ that reacted was:
0,2248 mol O₂× = <em>0,15 mol of KClO₃</em>
I hope it helps!