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sweet [91]
2 years ago
6

The unit of the electric resistance is ???​

Physics
1 answer:
vaieri [72.5K]2 years ago
7 0

Answer:

<h2>Ohms</h2>

Step-by-step-explanation :

Electric resistance

Dimension length :

Squared mass per time cubed , that is , electric current squared.

The SI derived unit of electric resistance is the ohm,(volt per ampere).

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Why do you lurch forward in a bus that suddenly slows? why do you lurch backward when it picks up speed? what law applies here?
AveGali [126]
The law applied here is Newton's first law, also known as, law of inertia.
This law states that: A body will retain its state of rest or motion unless acted upon by an external force.

If you are moving and the bus suddenly stops, your body will lurch forward trying to retain its state of motion until it comes to rest and changes its state by the external force acted on it.

If you are at rest and the bus suddenly moves, your body will lurch backwards trying to retain its state of rest and opposing the force of motion until it is forced to change its state by this force.
8 0
2 years ago
How much force is needed to accelerate a bicycle and rider with a total mass of 50 kg at a rate of 2.0 m/s2 ?
True [87]

Answer:

The answer is D 100 newton

Explanation:

2.0m/s2 is d acceleration while the 50kg is the mass. Force = mass x acceleration. So f=50x2.so force is 100 newton

8 0
2 years ago
How do you find density of a regular solid?
Effectus [21]
Put the object or material on a scale to figure out<span> its mass. 3. Divide the mass by the volume to </span>figure out the density<span> (p = m / v). You may also need to know </span>how to calculate<span> the volume of a </span>solid s<span>o use the formula</span>
3 0
3 years ago
Doc Brown has calculated his Delorean can accelerate at a rate of 2.52 m/s/s. How
GREYUIT [131]

Answer:

304.89m

Explanation:

Given

acceleration a = 2.52m/s²

final speed v = 39.2m/s

initial speed = 0m/s (car accelerates from rest)

Using the equation of motion below to get the distance of Doc brown from Marty;

v² = u²+2as

substitute the given parameters

39.2² = 0²+2(2.52)s

1536.64 = 0+5.04s

divide both sides by 5.04

1536.64/5.04 = 5.04s/5.04

rearrange the equation

5.04s/5.04 = 1536.64/5.04

s = 304.89m

Hence He and Marty must stand at 304.89m to allow the car to accelerate from rest to a speed  of 39.2 m/s?

6 0
3 years ago
Multiple choice please help :)
oee [108]

Answer:

oh i would have to do alot to answer that

7 0
3 years ago
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