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Zina [86]
3 years ago
5

4) The mass of Pluto is 1.31 x 1022 kg and its radius is 1.15 x 106 m. What is the acceleration of

Physics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

0.661 m/s²

Explanation:

g = MG / r²

g = (1.31×10²² kg) (6.67×10⁻¹¹ m³/kg/s²) / (1.15×10⁶ m)²

g = 6.61×10⁻¹ m/s²

g = 0.661 m/s²

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Answer:

When you exert a force on a baseball, there exists an equal and opposite force on the ball therefore, the ball will accelerate in opposite direction.

Explanation:

When you hit a ball with baseball bat, the bat exerts a great force on the ball which causes the ball to accelerate in the opposite direction. It is to be noted that the mass of bat is much greater than mass of ball but the acceleration of ball is also greater than the acceleration of the bat so both bat and ball almost exert same magnitude of force but in opposite direction and as a result both bat and ball accelerate in opposite direction, the deciding factor is of course the relative force applied by the batter and the bowler.

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An object of mass 30KG is falling in air and experiences a force due to air resistance of 50 newtons determine the net force act
ryzh [129]

Answer:

Assume that g = 10\; \rm N \cdot kg^{-1}. The net force on this object will be 250\; \rm N (downwards.) The acceleration of this object will be approximately 8.3\; \rm m \cdot s^{-2} (also downwards.)

Explanation:

<h3>Net force</h3>

The object is falling towards the ground because of gravity. The size of the gravitational force on this object depends on its mass and the strength of the gravitational field at its location.

Near the surface of the earth, the gravitational field strength is approximately 10\; \rm N \cdot kg^{-1}. In other words, approximately 10\; \rm N of gravitational force acts on each kilogram of mass near the surface of the earth.

The mass of this object is given as m = 30\; \rm kg. Therefore, the size of the gravitational force on it will be:

W = m \cdot g \approx 30 \; \rm kg \cdot 10\; N \cdot kg^{-1} = 300\; \rm N.

Near the surface of the earth, gravitational forces point towards the ground. On the other hand, the direction of air resistance on this object will be opposite to its direction of motion. Since this objects is moving towards the ground, the air resistance on it will be directed in the opposite direction. That's exactly the opposite of the direction of the gravitational force on this object. The net force on this object will be:

300\; \rm N - 50\; \rm N =250\; \rm N.

<h3>Acceleration</h3>

Let a denote the acceleration on this object. Apply Newton's Second Law of motion:

\begin{aligned} a &= \frac{F(\text{net force})}{m} \approx \frac{250\; \rm N}{30\; \rm kg} \approx 8.3\; \rm m \cdot s^{-2}\end{aligned}.

Note that the acceleration of this object and the net force on it should be in the same direction.

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