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Flauer [41]
3 years ago
8

The three types of nuclear radiation​

Physics
1 answer:
Eva8 [605]3 years ago
6 0
The three types are alpha beta and gamma
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Which particles are heavy and which are light
VashaNatasha [74]

Answer:

Protons and neutrons are heavy, Electrons are extremely light

Explanation:

Protons and neutrons are heavier than electrons and reside in the nucleus at the center of the atom. Electrons are extremely lightweight and exist in a cloud orbiting the nucleus.

3 0
3 years ago
Read 2 more answers
A 1200-kg car moving at 15.6 m/s suddenly collides with a stationary car of mass 1500 kg. if the two vehicles lock together, wha
g100num [7]
Use conservation of momentum ;

m1u1 + m2u2 = m1v1 + m2v2

1200×15.6 + 0 = 2700v

v = 18720/2700

v = 6.933 or ~ 7 m/s
5 0
3 years ago
A dog is 10 m from a cat, whose speeds are 6 and 5 m / s, respectively. What time does the dog require to catch the cat?
scoray [572]

Answer:

10 seconds

Explanation:

because the cat is moving one m/s slower than the dog, the dog has a relative speed of 1 m/s. 10 meters would take 10 seconds for the dog to cover

4 0
3 years ago
The c-cl bond dissociation energy in cf3cl is 339 kj/mol. What is the maximum wavelength of photons that can rupture this bond?
ruslelena [56]

Answer:

3.53*10^{-7} m

Explanation:

Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

1mol=6.022*10^{23}molecule

Hence, we have

E_d=339\frac{10^{3}J}{mol}*\frac{1mol}{6-022*10^{23}molecules}=5.62*10^{-19}J/molecule

but the energy is also:

E_d=h\nu =\frac{hc}{\lambda}\\\\\lambda=\frac{hc}{E_d}

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

\lambda=\frac{(6.62*10^{-34}Js)(3*10^{8}m/s)}{5.62*10^{-19}J}=3.53*10^{-7}m

hope this helps!

7 0
2 years ago
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A heat engine takes in 840 kJ per cycle from a heat reservoir. Which is not a possible value of the engine's heat output per cyc
zhannawk [14.2K]
We have by the first law of thermodynamics tha energy is preserved, hence we cannot have over 840kJ per cycle. We have by the laws of thermodynamics (the 2nd one in specific) that the entropy of a system cannot increase. We cannot have an output of  840 kJ per cycle from a heat engine because then that would mean that the entropy would stay the same, while any heat engine increases it. Hence, any value \geq 840 kJ is acceptable.
8 0
3 years ago
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