First, we determine how many electrons can each subshell hold:
s can hold 2 electrons
p can hold 6 electrons
d can hold 10 electrons
f can hold 14 electrons
Second, we start distributing the 10 electrons on the orbitals of subshells based on the arrangement shown in the question :
1s will hold 2 electrons
2s will hold 2 electrons
2p will hold 6 electrons
All other orbitals will will hold zero electrons as the 10 were distributed among the first 2
Answer: 1s: 2
2s: 2
2p: 6
<span> 3s: 0
3p: 0
4s: 0
3d: 0
4p: 0
5s: 0</span>
Answer:
1.48 moles of SeCl6 are needed
Explanation:
Based on the reaction:
SeCl6 + O2 → SeO2 + 3Cl2
<em>1 mole of SeCl6 reacts producing 3 moles of Cl2.</em>
To solve this question we need to use the conversion factor:
1mol SeCl6 = 3mol Cl2
As we want to produce 4.45 moles of Cl2, we need:
4.45 mol Cl2 * (1mol SeCl6 / 3mol Cl2) =
<h3>1.48 moles of SeCl6 are needed</h3>
Answer:
the heat energy is transformed to any kind of energy depending on what it's meant to be transformed to.
remember it cannot be destroyed so it's definitely transformed to some kinda energy
Answer:
330.95K
Explanation:
V₁ = 1.2L
T₁ = 25°C = (25 + 273.15)K = 298.15K
P₁ = 1.0 atm
P₂ = 0.74 atm
V₂ = 1.8L
T₂ =?
From combined gas equation,
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
Solve for T₂
T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)
T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)
T₂ = 397.1358 / 1.2
T₂ = 330.9465K
T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C
Answer:
6
Explanation:
Formula: Al2O3
If we require 2Al2O3
We divide 2 by 3
Sorry for the shadow of phone and fingers.
