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dimaraw [331]
3 years ago
6

What would the overall resistance be in a series circuit if there's an unknown R, 3Ω,3Ω and a current of 2A?

Physics
1 answer:
irinina [24]3 years ago
3 0

Answer:

R + 6 ohms

Explanation:

The current is the same in all three resistors

i = 2 amps

The problem is that the total voltage is unknown.

R = r

R1 =3 ohms

R2 = 3 ohms

The voltage drop is E = I*R

I = 2 amps

R1 = 3 ohms

R1 = 3 ohms

E = 3*2 = 6 volts

The second 3 ohm resistor also has 6 volts across it.

The total is 12 volts so far. But we know nothing more on how to solve for R.

All you can say is that the total resistance = R + 6 ohms

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Two remote control cars with masses of 1.16 kilograms and 1.98 kilograms travel toward each other at speeds of 8.64 meters per s
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The initial momentum of the system can be expressed as,

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The final momentum of the system can be given as,

p_f=m_1v_1+m_{2_{}}v_2

According to conservation of momentum,

p_i=p_f

Plug in the known expressions,

\begin{gathered} m_1u_1+m_2u_2=m_1v_1+m_2v_2 \\ m_2v_2=m_1u_1+m_2u_2-m_1v_1 \\ v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2} \end{gathered}

Initially, the second mass move towards the first mass therefore the initial speed of second mass will be taken as negative and the recoil velocity of first mass is also taken as negative.

Plug in the known values,

\begin{gathered} v_2=\frac{(1.16\text{ kg)(8.64 m/s)+(1.98 kg)(-3.34 m/s)-(1.16 kg)(-2.16 m/s)}}{1.98\text{ kg}} \\ =\frac{10.02\text{ kgm/s-}6.61\text{ kgm/s+}2.51\text{ kgm/s}}{1.98\text{ kg}} \\ =\frac{5.92\text{ kgm/s}}{1.98\text{ kg}} \\ \approx2.99\text{ m/s} \end{gathered}

Thus, the final velocity of second mass is 2.99 m/s.

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