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dimaraw [331]
3 years ago
6

What would the overall resistance be in a series circuit if there's an unknown R, 3Ω,3Ω and a current of 2A?

Physics
1 answer:
irinina [24]3 years ago
3 0

Answer:

R + 6 ohms

Explanation:

The current is the same in all three resistors

i = 2 amps

The problem is that the total voltage is unknown.

R = r

R1 =3 ohms

R2 = 3 ohms

The voltage drop is E = I*R

I = 2 amps

R1 = 3 ohms

R1 = 3 ohms

E = 3*2 = 6 volts

The second 3 ohm resistor also has 6 volts across it.

The total is 12 volts so far. But we know nothing more on how to solve for R.

All you can say is that the total resistance = R + 6 ohms

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solong [7]

Answer:

521 nm

Explanation:

Given the values and units we are given, I'm assuming  5.76*10^14 Hz is frequency.

The formula to use here is λ * υ = c, where λ is wavelength, υ is frequency, and c is the speed of light.

λ = \frac{3*10^8\frac{m}{s} }{5.76*10^{14}Hz} = {5.20833*10^{-7} m}\approx{521 *10^{-9}m}={521 nm}

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2 years ago
To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed o
Rudiy27
9.6m/s - apex .........................
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Question is down below
rosijanka [135]

The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

<h3>What are the components of velocity?</h3>

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

Hence;

Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

Horizontal component = 40 cos 15 degrees = 38.6 m/s

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7 0
1 year ago
What is not an example of Absorption? (Physics)
amm1812

When a light wave strikes an object, it can be absorbed, reflected, or refracted by the object. All objects have a degree of reflection and absorption. ... In the natural world, light can also be transmitted by an object. That is, light can pass through an object with no effect (an x-ray, for example).

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2 years ago
A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertica
Radda [10]

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Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed \omega =40rad/s

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let \omega _2 be the final angular velocity of cylinder

Conserving Angular momentum

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\left ( \frac{18\cdot 1.7^2}{2}\right )\cdot 40=\left ( \frac{18\cdot 1.7^2}{2}+0.8\cdot 0.3^2\right )\omega _2

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