Answer:
P.E = 82320 joules
Explanation:
Given,
The mass of the squirrel, m = 700 Kg
The squirrel leaped to a height, h = 12 m
The acceleration due to gravity, g = 9.8 m/s²
The potential energy of a body is possessed by its height. It is given by the formula
P.E = mgh joules
Substituting the values in the above equation
P.E = 700 Kg x 9.8 m/s² x 12 m
= 82320 joules
The Potential Energy of the squirrel is, P.E = 82320 joules
You have to use the specific heat equation.
Q = cmΔT where Q is the energy, c is specific heat, m is mass, and ΔT is change in temp.
So we can substitute our variables into the equation.
30000J = (390g)(3.9J*g/C)ΔT
Solving for ΔT, we get:
30000J/[(390g)*(3.9J*g/C) = ΔT
ΔT = 19.72386588C
I'm assuming the temperature is C, since it was not specified.
Hope this helps!