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aleksklad [387]
3 years ago
7

What is Restoring force for large waves is A. Wind, B. Capillary Action, C. Diffusion D.Friction, or E. Gravity

Physics
1 answer:
jek_recluse [69]3 years ago
7 0
The answer would be c.diffution
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Please answer-WILL MARK THE BEST ANSWER AS BRAINLIEST (100 POINTS)
Masja [62]

Answer:

The Earth’s lithosphere, which includes the crust and upper mantle, is made up of a series of pieces, or tectonic plates, that move slowly over time.

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth’s mantle to the surface, solidifying to create new oceanic crust. The Mid-Atlantic Ridge and Pacific Ring of Fire are two examples of divergent plate boundaries.

When two plates come together, it is known as a convergent boundary. The impact of the colliding plates can cause the edges of one or both plates to buckle up into a mountain ranges or one of the plates may bend down into a deep seafloor trench. A chain of volcanoes often forms parallel to convergent plate boundaries and powerful earthquakes are common along these boundaries.

At convergent plate boundaries, oceanic crust is often forced down into the mantle where it begins to melt. Magma rises into and through the other plate, solidifying into granite, the rock that makes up the continents. Thus, at convergent boundaries, continental crust is created and oceanic crust is destroyed.

Two plates sliding past each other forms a transform plate boundary. One of the most famous transform plate boundaries occurs at the San Andreas fault zone, which extends underwater. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions. Rocks that line the boundary are pulverized as the plates grind along, creating a linear fault valley or undersea canyon. Earthquakes are common along these faults. In contrast to convergent and divergent boundaries, crust is cracked and broken at transform margins, but is not created or destroyed.

5 0
2 years ago
Read 2 more answers
At the end of a race a runner decelerates from a velocity of 11.00 m/s at a rate of 0.300 m/s2. (a) how far does she travel in t
inessss [21]

given that initial velocity is

v_i = 11 m/s

deceleration is given as

a = -0.3 m/s^2

now we have to find the distance covered in 16 s

d = v_i * t + \frac{1}{2} at^2

d = 11*16 - \frac{1}{2}*0.3*16^2

d = 137.6 m

so it will cover 137.6 m distance

part b)

in order to find the final speed

v_f = v_i + at

v_f = 11 - 0.3*16

v_f = 6.2 m/s

so its speed will be 6.2 m/s

8 0
3 years ago
Find the initial velocity of a car which stops in 10sec, after applying brakes at the rate of 2m/s²
Dennis_Churaev [7]

Answer:

20\ m/s

Explanation:

Since we are given time, acceleration, and final velocity, we can use the following formula to find the initial velocity:

v_f = v_i + at

Our given values:

v_f = 0\\a = -2\\t = 10\\

<em>Acceleration is negative because the car is slowing down.</em>

Add the values to the formula, and solve for v_i:

v_f = v_i + at\\0 = v_i + (-2)(10)\\0 = v_i -20\\20 = v_i

7 0
2 years ago
A 1200 kg truck accelerates from 25 m/s to 53 m/s over a distance of 350 m.
sveticcg [70]

Answer:

the average net force on the truck is 3744 N.

Explanation:

Given;

mass of the truck, m = 1200 kg

initial velocity of the truck, u = 25 m/s

final velocity of the truck, v = 53 m/s

distance traveled by the truck, d = 350 m

The acceleration of the truck is calculated as;

v² = u² + 2ad

53² = 25² + (2 x 350)a

700a = 53² - 25²

700a = 2184

a = 2184 / 700

a = 3.12 m/s²

The average net force on the truck is calculated as;

F = ma

F = 1200 x 3.12

F = 3744 N

Therefore, the average net force on the truck is 3744 N.

6 0
3 years ago
You calibrate a set of automobile springs using a 25 kg car battery, attached to a rope that runs over a pulley, as shown in the
Goshia [24]

For an automobile spring using a 25 kg car battery, the spring constant is mathematically given as

K=4.08.3N/m

<h3>What is the spring constant?</h3>

Question Parameter(s):

a 25 kg car battery

The springs are pulled out by 0.06 meters

Generally, the equation for the Force  is mathematically given as

F=mg

Therefore

F=(25*9.8)

(25*9.8)=K(0.06)

K=4.08.3N/m

In conclusion, the spring constant

K=4.08.3N/m

Read more about Force

brainly.com/question/13370981

3 0
2 years ago
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