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3 years ago

A location along stream where most erosions occur

Chemistry

1 answer:

vagabundo [1.1K]3 years ago

4 0

Answer:

At a stream's headwaters, often high in the mountains, gradients are steep. The stream moves fast and does lots of work eroding the stream bed.As a stream moves into lower areas, the gradient is not as steep. Now the stream does more work eroding the edges of its banks.

hope that helps bby<3

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If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so

sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂ → Mg²⁺ + 2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

MgCl₂ → Mg²⁺ + 2Cl⁻

0.12mol 0.12 0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)

8 0

2 years ago

You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el

Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.

For example;

Given a number 5;

We know the number is made of both the atomic number of the element and the highest quantum number.

It is easier for us to know the highest quantum number from the shell notation:

shell notation 1s²2s²2p¹

highest principal quantum number is 2

We are left with atomic number 5-2, which is 3

The element is therefore Li.

Part A. 5, 30, 58, 56, 99, 79, 19, 98, 9

Li Fe I Sb U Ta S Pa N

Part B. 9, 99, 30, 95, 19, 47, 79

N U Fe Ra S Mo Ta

Learn more:

s-orbital brainly.com/question/9288609

#learnwithBrainly

4 0

3 years ago

How much energy is used to melt 44.33 g of solid oxygen?

Nutka1998 [239]

Answer:

Q1 = C * m * dT

Q2 = Qm * m

Qtotal = Q1 + Q2

Q1 - is amount of energy you need to apply to heat oxygen from the current temperature till you reach the melting temperature. Only if the oxygen is below to melting temperature.

C - is calorific capacity of oxygen -- better look at tables, it is a constant value

m - is the amount of oxygen, we will use moles because the other data shows moles, but could be grams, kg, etc.

dT - is the diference of temperatures between the current and the melting one. The melting temperature is constant and you can find it on tables, then (Tm - To)

Q2 is the amount of energy you have to add to melt oxygen once the oxygen has reached the melting temperature (Tm)

Qm is a constant value you could find on tables, depends on the mass of oxygen and is due to internal processes as changes in atomic distributions

If the oxygen is initially at melting temperature (melting point) you only need to know Q2, as dT = 0

I will do an example for you, but in future you should provide data of constants, it takes very long to find them in books or internet.

Data from tables

Tm = 54.36 K

C = 29.378 J/mol K this is at 25 C (or 298 K), is not really correct, you should look at its value at less than 54.36 K, but you can use it here.

Qm = 0.444 kJ/mol

Problem -- you have 44.33g of Oxygen -- Molecular weight of O2 is 32 g/mol

So you have 44.33/32 = 1.385 moles of oxygen

a) if oxygen is already at melting temperature: you only have to melt it

Qtotal = Q1 + Q2 = [0 (dT = 0) + Qm * m] = 0.444 * 1.385 = 0.615 kJ = 615 J