If a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
<h3>How to calculate mass percent?</h3>
The mass percent of hydrate in a sample can be calculated by dividing the mass of water in the sample by the mass of the hydrated compound.
According to this question, 3.50g sample of an hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate. The mass percent of water is calculated as follows:
Mass percent of water = (3.5-2.1)/3.5 × 100
Mass percent of water = 40%
Therefore, if a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
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Answer:
Option A.
Explanation:
Probability is expressed in percent, fraction or in whole numbers
The new volume : V₂ = 2454.8 L
<h3>Further explanation</h3>
Given
V₁=2240 L
P₁=760 mmHg
T₁=320 K
P₂=700 mmHg
T₂=323 K
Required
Volume V₂
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K
V₂=(P₁V₁T₂)/P₂T₁
V₂=(760 x 2240 x 323)/(700 x 320)
V₂ = 2454.8 L
Answer:
The answer to the question is 0.2376moles
50 you always use the the top number for protons