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2 years ago

What is flame over circle mean?

2 answers:

7 0

Flame over Circle. This symbol on a chemical label means that the substance is an oxidizer. Oxidizers may cause a fire by increasing the concentration of oxygen in the air.

Dominik [7]2 years ago

5 0

That means flammable

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Which of the following is NOT correct about elements?

Lynna [10]

Answer: B. Elements are represented by chemical formulas.

Elements are pure substances, which means that they cannot be broken down into simpler substances. The element is the most basic substance that exists, breaking it down further means breaking it down into protons, neutrons, and electrons, which is no longer a substance.

Elements have chemical properties that allow them to form different types of bonds with other elements.

However, elements *alone* are not represented by their chemical formulas. Only chemical bonds or ions are represented by a chemical formula.

3 0

3 years ago

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Identify the large brown tectonic plate and whether it is oceanic or continental.

Lady_Fox [76]

I found the image and the given choices. The choices were:

Eurasian, continental
South American, oceanic 
African, oceanic 
North American, continental

Based on the image, the large brown tectonic plate is NORTH AMERICA and it is a continental plate.

3 0

3 years ago

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Rutherford proposed that atoms have positive nuclei. Which statement correctly describes the nucleus of an atom?

DIA [1.3K]

I'm not 100% sure but I'm leaning towards D. :)

8 0

3 years ago

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A 45-g aluminium spoon(specific heat 0.80 / J/gdegree Celsius) at 24 degree celsius is placed in 180 ml(180 grams) of coffee at

Vlad [161]

Explanation:

a) The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, $heat_{absorbed}=heat_{released}$

To calculate the amount of heat released or absorbed, we use the equation:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

Also,

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ..........(1)

where,

q = heat absorbed or released

$m_1$ = mass of aluminium = 45 g

$m_2$ = mass of coffee = 180 g

$T_{final}$ = final temperature = ?

$T_1$ = temperature of aluminium = $24^oC$

$T_2$ = temperature of coffee = $85^oC$

$c_1$ = specific heat of aluminium = $0.80J/g^oC$

$c_2$ = specific heat of coffee= $4.186 J/g^oC$

Putting all the values in equation 1, we get:

$45 g\times 0.80J/g^oC\times (T_{final}-24^oC)=-[180 g\times 4.186J/g^oC\times (T_{final}-83^oC)]$

$T_{final}=80.30^oC$

80.30 °C is the final temperature.

b) Energy flows from higher temperature to lower temperature.Whenever two bodies with different energies and temperature come in contact. And the resulting temperature of both bodies will less then the body with high temperature and will be more then the body with lower temperature.

So, is our final temperature of both aluminium and coffee that is 80°C less than initial temperature of coffee and more than the initial temperature of the aluminum.

8 0

2 years ago

HELP ASAP!!

Harman [31]

I would think it is a heterogeneous mixture since it can't be an element since there are more than one type of atom, it can't be a compound since the leaves are not bonded together, and it can not be a homogeneous mixture since the leaves don't all blended together (the pile is not uniform) and you can distinguish all the different parts of the mixture. It can be considered a heterogeneous mixture since the leaves are mixed together (along with other things like dirt) in a non-uniform way so that you can point out the parts of the mixture and it does not look like one thing.

I hope this helps. Let me know in the comments if anything is unclear.

4 0

2 years ago