1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sleet_krkn [62]
3 years ago
5

What is flame over circle mean?

Chemistry
2 answers:
Tom [10]3 years ago
7 0
Flame over Circle. This symbol on a chemical label means that the substance is an oxidizer. Oxidizers may cause a fire by increasing the concentration of oxygen in the air.
Dominik [7]3 years ago
5 0
That means flammable
You might be interested in
A researcher wants to determine if a unicellular organism he discovered is an autotroph or a heterotroph. He radioactively label
GaryK [48]

Answer:

A

Explanation:

Autotrophs utilize the energy from  sunlight to reduce carbon dioxide to carbohydrates (glucose). The energy from the sunlight is used to split water into H+ and O2- and the H+ used in the reduction process. The labeled carbon in the carbon dioxide will, therefore, be incorporated by the autotrophs in the carbohydrates made in photosynthesis.  

4 0
3 years ago
What energy levels are core electrons in?
a_sh-v [17]

core electrons are those occupying the innermost or lowest energy levels

4 0
2 years ago
1. How many moles of CO2 can be produced from a reaction of 10.0 moles CzHg?
mr_godi [17]

Answer:

20 moles of CO2 can be produced from a reaction of 10.0 moles C2H6

Explanation:

In this reaction -

2 moles of C₂H6 produces four molecules of Carbon dioxide (CO2)

So 1 mole of C₂H6 will produce \frac{4}{2} = 2 moles of Carbon dioxide (CO2)

Thus, 10 moles of C₂H6 will produce 2 * 10 = 20 moles of Carbon dioxide (CO2)

3 0
3 years ago
It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min
kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 8.1\times 10^{-2} min⁻¹

Initial concentration [A_0] = 0.1 M

Final concentration [A_t] = 1.0\times 10^{-2} M

Time = ?

Applying in the above equation, we get that:-

1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}

0.1e^{-8.1\times \:10^{-2}t}=10^{-2}

e^{-8.1\times \:10^{-2}t}=\frac{1}{10}

\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)

t=28.43\ min

3 0
3 years ago
How can melting point and boiling point identify a substance
Nikolay [14]

Answer:

to determine of it is a solid liquid or gas.

Explanation:

The melting point is the temperature at which a substance converts from a solid state to a liquid state.

8 0
3 years ago
Other questions:
  • What does tectonic activity refer to
    14·1 answer
  • 2al2o3 4al 3o2 what is the mole ra#tio of aluminum to oxygen is 4:3
    11·1 answer
  • velocity and time information for a leftward moving car are shown. t = 4.0s v= 4.0 m/s. t = 0.0 v=20.0 m/s. what is the magnitud
    8·1 answer
  • What mass of oxygen (O2) forms in a reaction that forms 15.90 g C6H12O6? (Molar mass of O2 = 32.00 g/mol; molar mass of C6H12O6
    13·2 answers
  • The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1
    14·1 answer
  • Define the following terms . <br>1. Element <br>2. Mixture <br>3. Compound <br>​
    15·1 answer
  • Jean and her mother were taking a walk when they saw the two rocky outcrops in the diagram below.
    15·1 answer
  • Based on the information below, both Polaris and Sirius are much hotter than the Sun. However, on Earth, we feel the heat from t
    9·2 answers
  • Do you use sig figs in percent errors??
    9·1 answer
  • Rank the substances involved in this reaction in the order of decreasing potential energy:
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!