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3 years ago

How is specific heat capacity related to a change in state of matter?

1 answer:

4 0

The heat capacity or thermal capacity of a body is the quotient between the amount of heat energy transferred to a body or system in any process and the change in temperature it experiences. In a more rigorous form, it is the energy necessary to increase the temperature of a certain substance by one temperature unit. [1] It indicates the greater or lesser difficulty that said body presents in experiencing changes in temperature under the supply of heat. It can be interpreted as a measure of thermal inertia. It is an extensive property, since its magnitude depends not only on the substance but also on the amount of matter in the body or system; therefore, it is characteristic of a particular body or system. For example, the heat capacity of the water in an Olympic-size swimming pool will be greater than that of the water in a glass. In general, heat capacity also depends on temperature and pressure.

Explanation:

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Consider the reaction pathway graph below.

Artemon [7]

E and Dis determine the H

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3 years ago

Read 2 more answers

During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce

swat32

Answer: 16.32 g of $O_2$ as excess reagent are left.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol$

$\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol$

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

According to stoichiometry :

2 moles of $SO_2$ require = 1 mole of $O_2$

Thus 0.34 moles of $SO_2$ will require= $\frac{1}{2}\times 0.34=0.17moles$ of $O_2$

Thus $SO_2$ is the limiting reagent as it limits the formation of product and $O_2$ is the excess reagent.

Moles of $O_2$ left = (0.68-0.17) mol = 0.51 mol

Mass of $O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g$

Thus 16.32 g of $O_2$ as excess reagent are left.

3 0

3 years ago

PLZ HELP ASAP

GrogVix [38]

Answer:

The second option

Explanation:

Speed is defined at the rate at which distance changes with time. It is scalar quantity and it is expressed as shown below:

Speed = $\frac{distance}{time}$

At constant speed the rate of change of distance with time is the same. On the second graph, this is noticeable. Both distance and time change at the same rate.

7 0

3 years ago

Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. Calculate the expected yield of

Lelu [443]

Answer:

53kg is the expected yield of lead

Explanation:

Firstly, in order to solve this question, we need to write the equation of reaction correctly. This is as follows:

PbO(s) + C(s) ---> Pb(l) + CO(g)

We proceed from here. We should get the limiting reactant but this can only be obtained by getting the number of moles of each reactant present.

The formula to use across all boards is that the number of moles is the mass of each of the reactant divided by the molar mass of each of the reactant.

For PBO, mass is 57kg = 57000g

Molar mass of PBO = 223.20g/mol

The number of moles is thus 57,000/223.2 = 255.37 moles

For carbon, mass is also 57kg = 57000g

Molar mass is 12g/mol

Number of moles of carbon = 57000/12 = 4750 moles

From the number of moles, we can see that the number of moles of Carbon is greater than that of PbO. This means that PbO is the limiting reagent.

Hence we use it to calculate percentage yield.

The number of moles of lead formed is the same of number of moles of lead oxide = 255.37 since we have mole ratio of 1 to 1

The molar mass of lead is 207.20g/mol

The mass of lead formed is = moles of lead formed * molar mass of lead = 207.20 * 255.37 = 52,912g which is approximately 53kg

Hence the expected yield is 53kg

6 0

3 years ago

What is the pH of 15 mL of .2 M HCl

fenix001 [56]

Easy peasy! All we need to do is plug this formula into our calculator:

-log(M)

So, we'd plug in -log(.2), which is 0.7 :)

3 0

3 years ago