3 years ago

Which of the following statements is not correct?

Chemistry

2 answers:

Lilit [14]3 years ago

8 0

Answer:

It's 4.1 moles Li2O = 94 g on Odyssey ware

avanturin [10]3 years ago

3 0

Answer:

4.1 moles Li2O = 94 g (incorrect)

4.1 mole of Li2O = 122.6g(correct)

Explanation:

1. Molar mass of O2 = 32

0.2 mole of 32 = 0.2×32 = 6.4g (correct)

2. Molar mass of H2CO3 = 62.03

0.75 mole of 62.03 = 0.75×62.03 = 46.5g (47 is correct)

3. Molar mass of CO = 28

3.42 moles of 30 = 3.42×28 = 95.76 (95.8 is correct)

4. Molar mass of Li2O = 29.9

4.1 mole of Li2O = 4.1×29.9 = 122.59g (94g is incorrect)

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$m=1.325gNa_2CO_3$

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Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

$eq-g=0.5eq-g/L*0.050L=0.025eq-g$

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

$mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3$

Finally, the mass is computed by using its molar mass (106 g/mol)

$m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3$

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