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3 years ago

12

You stretch a spring ball system 0.552 m away from its equilibrium point and watch it oscillate. You find that the system's angu

lar frequency is 1.42 rad/sec. What is the maximum speed of the ball?

1 answer:

4vir4ik [10]3 years ago

3 0

Answer:

The maximum speed of ball is 0.784 m/s.

Explanation:

Given that,

Amplitude = 0.552 m

Angular frequency = 1.42 rad/s

We need to calculate the maximum speed of ball

Using formula of speed

$v=A\omega$

Where, A = amplitude

$\omega$ = angular frequency

Put the value into the formula

$v=0.552\times1.42$

$v=0.784\ m/s$

Hence, The maximum speed of ball is 0.784 m/s.

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