Question

You stretch a spring ball system 0.552 m away from its equilibrium point and watch it oscillate. You find that the system's angular frequency is 1.42 rad/sec. What is the maximum speed of the ball?

Answer 1

Answer:

The maximum speed of ball is 0.784 m/s.

Explanation:

Given that,

Amplitude = 0.552 m

Angular frequency = 1.42 rad/s

We need to calculate the maximum speed of ball

Using formula of speed

$v=A\omega$

Where, A = amplitude

$\omega$ = angular frequency

Put the value into the formula

$v=0.552\times1.42$

$v=0.784\ m/s$

Hence, The maximum speed of ball is 0.784 m/s.