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Mumz [18]
3 years ago
12

You stretch a spring ball system 0.552 m away from its equilibrium point and watch it oscillate. You find that the system's angu

lar frequency is 1.42 rad/sec. What is the maximum speed of the ball?
Physics
1 answer:
4vir4ik [10]3 years ago
3 0

Answer:

The maximum speed of ball is 0.784 m/s.

Explanation:

Given that,

Amplitude = 0.552 m

Angular frequency = 1.42 rad/s

We need to calculate the maximum speed of ball

Using formula of speed

v=A\omega

Where, A = amplitude

\omega = angular frequency

Put the value into the formula

v=0.552\times1.42

v=0.784\ m/s

Hence, The maximum speed of ball is 0.784 m/s.

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REY [17]

Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

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Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

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Then the net magnitude of momentum is P = (Px2 + Py2)1/2

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Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

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3 years ago
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A body weighs 63 N on the surface of the earth. What is the gravitational force on
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Answer:

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