All categories

3 years ago

A high frequency sound will have a ?

Physics

2 answers:

stepladder [879]3 years ago

7 0

Answer:

The frequency of a sound wave is what your ear understands as pitch. A higher frequency sound has a higher pitch and the lower the period

masya89 [10]3 years ago

6 0

Answer:

High-frequency sound waves produce high-pitched sounds, and low-frequency sound waves produce low-pitched sounds.

You might be interested in

A very light ideal spring having a spring constant (force constant) of 8.2 N/cm is used to lift a 2.2-kg tool with an upward acc

vampirchik [111]

Answer:

x = 3.5 cm

Explanation:

When spring is used as a lift tool

so the mass suspended on it will have spring force on it

So as per the force equation of mass we can say

$F_{net} = ma$

now net force on the mass is

$F_{net} = kx - mg$

$F_{net} = kx - mg = ma$

here we have

$kx = mg + ma$

now we have

$x = \frac{mg + ma}{k}$

$x = \frac{2.2(9.8) + 2.2(3.25)}{8.2}$

$x = 3.5 cm$

6 0

4 years ago

Which ball has the greater acceleration at the instant of release?

yuradex [85]

They're equal.

Ignoring air resistance, any object you're not holding onto has the same, constant acceleration ... 9.8 m/s^2 down ... from the moment it leaves your hand until the moment it hits the ground.

It doesn't matter how heavy the object is, and it doesn't matter whether you throw it up, down, or sideways, or just let go and let it drop.

6 0

3 years ago

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m

Degger [83]

Answer:

a)t = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s ; V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ and V₀y = 0

And at the end of the movement t = ? the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9 ⇒ t² = 2,04 s

t = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ V₀y = 0 and V₀ₓ = Vₓ ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then 15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf = 0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

3 0

4 years ago

A block of mass m = 2.5 kg is attached to a spring with spring constant k = 730 N/m. It is initially at rest on an inclined plan

Alona [7]

Answer:

A) Em = 4.41 J

B) L = 0.33m

Explanation:

A) The total mechanical energy of the block is the elastic potential energy due to the compressed spring. The gravitational energy is zero. Then you have:

$E_m=\frac{1}{2}k(\Delta x)^2$

k: constant's spring = 730 N/m

Δx: distance of the compression = 0.11m

You replace the values of k and Δx:

$E_m=\frac{1}{2}(730N/m)(0.11m)^2=4.41\ J$

B) To find the distance L traveled by the block you take into account that the total mechanical energy of the block is countered by the work done by the friction force, and also by the work done by the gravitational energy.

Then, you have:

$E_m-W_f-W_g=0\\\\W_f=(\mu Mg cos\theta)L\\\\W_g=(Mgsin\theta)L$