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zmey [24]
3 years ago
12

;-; please help me....​

Physics
1 answer:
sineoko [7]3 years ago
5 0
The answer is 24N. Since the body is moving with constant velocity all the forces must balance (equal & opposite)
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What kind of energy involves the flow of charged particles?
Citrus2011 [14]

Answer:

Electrical energy is answer

Explanation:

hope it helps

Mark me as brainliest plz.

3 0
3 years ago
What is the final velocity of the ball that is dropped from a height of 200m?
Hoochie [10]

The final velocity of the ball that is dropped from a height of 200m is v = 44.73 m/s .

<h3>What is velocity with example?</h3>

The rate at which an object is travelling in one direction is referred to as its velocity. an automobile traveling north on a highway, or a rocket taking off. Its velocity vector's absolute value always is equal to the motion's speed because it is a scalar.

<h3>Briefing:</h3>

Given the initial velocity of the ball (u) =  0

Distance travelled by the ball (s) = 200m

Acceleration (a) = 10 m/s²

As we know:

v² = u² + 2as

Putting values:

v² = 0+2 × (10 m/s²) × (200 m)

v = 44.73 m/s.

To know more about Velocity visit:

brainly.com/question/18084516

#SPJ9

8 0
1 year ago
Compute the order of magnitude of the mass of a bathtub half full of pennies. (Assume the pennies are made entirely of copper.)
devlian [24]

Answer:

Mass = 873.6kg = 0.874 × 10^3 kg

Order = 3

Question:

Compute the order of magnitude of the mass of a bathtub half full of pennies.(Assume the pennies are made entirely of copper and the tub measures 1.3 m by 0.5 m by 0.3 m)

Explanation:

Given:

Dimensions of the tub = 1.3 m by 0.5 m by 0.3 m

Density of copper d = 8960kg/m^3

Mass = volume × density

Volume of tub = L×B×H = 1.3 × 0.5 × 0.3 = 0.195m^3

Since the tub is half full:

V = 0.195/2 = 0.0975m^3

Mass = 8960kg/m^3 × 0.0975m^3

Mass = 873.6kg = 0.874 × 10^3 kg

Order = 3

Note: Order of magnitude is of the form:

N = a × 10^b

Where;

b = order of magnitude

and

1/√10 </= a < √10

8 0
4 years ago
A brass cube, 10 cm on a side, is raised in temperature
lana [24]

Answer:

\delta L\%=22.5\%

Explanation:

<em>Assuming that the thermal expansion of brass cube occurs isotropically (i.e. equal in all the directions).</em>

Given:

  • length of the cube, l=10\ cm=0.1\ m
  • change in temperature of the cube, \Deta T=200\^{\circ}C
  • coefficient of volume expansion, \beta=57\times 10^{-6}\ ^{\circ}C^{-1}

<u>Hence volume of the cube:</u>

V=10^{-3}\ m^3

Now the volume of the cube after expansion:

\delta V=V.\beta.\Delta T

\delta V=10^{-3}\times 57\times 10^{-6}\times 200

\delta V=1.14\times 10^{-5}\ m^3

Therefore,

\delta L=0.0225\ m

<u>Now the percentage change in the edges of the cube:</u>

\delta L\%=\frac{\delta L}{L} \times 100

\delta L\%=\frac{0.0225}{0.1} \times 100

\delta L\%=22.5\%

5 0
3 years ago
A cube of copper 2.00cm on a side is suspended by a string. The cube is heated with a burner from 20.0°C to 90.0°C. The air surr
riadik2000 [5.3K]

Answer:

a. 2.856 x 10^-6 m³

b. 0.288 J

c. 971.88 J

d. 971.592 J

Explanation:

d) The change in internal energy of the cube.

Note: For Copper -

B(beta)= 5.1 × 10^-3 (C)^-1

Cp = 390J/Kg.K

p (Rho) = 8.90 × 10³Kg/m³

Detailed solution is attached below

5 0
3 years ago
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