1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galina1969 [7]
2 years ago
15

A student was traveling to see his grandmother who lives 15 miles north oh his home he started from rest and maintained a pace o

f 4 m/s before stopping at his grandmother's house for lunch which of the following best describes the speed, velocity and acceleration of the student's walk?
Physics
1 answer:
N76 [4]2 years ago
3 0

Explanation:

Given parameters:

Distance  = 15miles north = 24140.2m

Initial velocity  = 0m/s

Final velocity  = 4m/s

Unknown:

Speed, velocity and acceleration = ?

Solution:

The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.

  Speed  = \frac{distance }{time}  

  The speed of the student is 4m/s

Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;

    Velocity  = \frac{displacement}{time}  

   The velocity of the student is 4m/s due north

Acceleration is the change in velocity with time;

     To find the acceleration, we use

      v²  = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

     4² = 0² + 2x a x 24140.2

       a  = \frac{16}{2 x 24140.2}  = 0.00033m/s²

You might be interested in
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 6.0 rev/s in 11.0 s. At th
sleet_krkn [62]

Answer

given,

ω₁ = 0 rev/s

ω₂ = 6 rev/s

t = 11 s

Using equation of rotational motion

The angular acceleration is

  ωf - ωi = α t

  11 α = 6 - 0

      = 0.545 rev/s²

The angular displacement

  θ₁= ωi t + (1/2) α t²

  θ₁= 0 + (1/2) (0.545)(11)^2

  θ₁= 33 rev

case 2

ω₁ = 6 rev/s

ω₂ = 0 rev/s

t = 14 s

Using equation of rotational motion

The angular acceleration is

  ωf - ωi = α t

  14 α = 0 - 6

        = - 0.428 rev/s²

The angular displacement

  θ₂= ωi t + (1/2) α t²

  θ₂= 6 x 14 + (1/2) (-0.428)(14)^2

  θ₂= 42 rev

total revolution in 25 s is equal to

θ =  θ₁ +  θ₂

θ =  33 + 42

θ = 75 rev

3 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016 Na+ ions arrive at the negative electrode and 3.
sladkih [1.3K]

Answer:

10.6 mA

Explanation:

t = time interval = 1.00 s

q = magnitude of charge on each ion = 1.6 x 10⁻¹⁹ C

n₁ = number of Na⁺ ions = 2.68 x 10¹⁶

q₁ = charge due to Na⁺ ions = n₁ q = (2.68 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.004288 C

n₂ = number of Cl⁻ ions = 3.92 x 10¹⁶

q₂ = charge due to Cl⁻ ions = n₂ q = (3.92 x 10¹⁶) (1.6 x 10⁻¹⁹) = 0.006272 C

i₁ = Current due to Na⁺ ions = \frac{q_{1}}{t} = \frac{0.004288}{1} = 0.004288 A

i₂ = Current due to Cl⁻ ions = \frac{q_{2}}{t} = \frac{0.006272}{1} = 0.006272 A

Current passing between the electrodes is given as

i = i₁ + i₂

i = 0.004288 + 0.006272

i = 0.01056 A

i = 10.6 x 10⁻³ A

i = 10.6 mA

8 0
3 years ago
If all the light waves are reflected in equal amounts off an object then the object will appear
Fantom [35]
The object would appear bright
3 0
3 years ago
Read 2 more answers
99 POINTS
antoniya [11.8K]

Answer:

Send a pic of it so i can mark it.

Explanation:

8 0
3 years ago
To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 57.0° above the ho
cupoosta [38]

Answer:

xf = 5.68 × 10³ m  

yf = 8.57 × 10³ m  

Explanation:

given data

vi = 290 m/s

θ = 57.0°

t = 36.0 s

solution

firsa we get here origin (0,0) to where the shell is launched

xi = 0                            yi = 0

xf = ?                            yf = ?

vxi =  vicosθ               vyi = visinθ  

ax = 0                          ay = −9.8 m/s

now we solve x motion: that is

xf = xi + vxi × t + 0.5 × ax × t²     ............1

simplfy it we get

xf = 0 + vicosθ × t + 0

put here value and we get

xf = 0 + (290 m/s) cos(57) (36.0 s)

xf = 5.68 × 10³ m  

and

now we solve for y motion: that is

yf = yi + vyi × t + 0.5 × ay × t ²     ............2

put here value and we get

yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s)  ²

yf = 8.57 × 10³ m  

5 0
3 years ago
Other questions:
  • 34.6 cL= (blank) hL convert
    12·1 answer
  • A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is the value of the rms curren
    14·1 answer
  • During its final days as a red giant, the Sun will reach a peak luminosity of about 3000LSun. Earth will therefore absorb about
    14·1 answer
  • Can anyone solve this please.........
    14·1 answer
  • SOMEONE HELP PLEASE 20 POINTS
    14·2 answers
  • Please help! 30Points!! An ultrasound machine uses waves to create images. The machine uses sound waves and which wave interacti
    6·2 answers
  • What is a type of force that results from turning a corner on a bicycle? ​
    11·2 answers
  • What is buoyancy? How is it related to the force of gravity?
    13·1 answer
  • 6
    12·1 answer
  • How did the discovery of eris force astronomers to reconsider the definition of planet?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!