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Varvara68 [4.7K]
3 years ago
14

Can someone help me? In this net, the two triangles are right triangles. All quadrilaterals are rectangles. What is its surface

area in square units? Do not include units (square units) in your answer.
Mathematics
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Net Area = 168

Step-by-step explanation:

See attachment for complete question

I'll make reference to the attachment, when needed.

The shapes that make up the net are labelled 1 to 5.

So, to calculate the surface area of the net, we simply calculate the surface area of each label.

Label 1: Rectangle

Area = Length * Width

Area = 10 * 5

Area = 50

Label 2: Rectangle

Area = Length * Width

Area = 8 * 5

Area = 40

Label 3: Rectangle

Area = Length * Width

Area = 6 * 5

Area = 30

Label 4: Triangle

Area = ½Base * Height

Base = 6 and Height = 8

So:

Area = ½ * 6 * 8

Area = 24

Label 5: Triangle

Area = ½Base * Height

Base = 6 and Height = 8

So:

Area = ½ * 6 * 8

Area = 24

So, the net area is the summation of the calculated areas of label 1 to 5

Net Area = 50 + 40 + 30 + 24 + 24

Net Area = 168

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2 years ago
Write an equation for a direct variation that includes the point (3, 18)
erma4kov [3.2K]
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m = \frac{y_2 - y_1}{x_2 - x_1}
m = \frac{18 - 0}{3 - 0}
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Now that you know the slope of the line you are looking for is 6, you can plug that into a point-slope form equation and find the equation of your line.

y - y_1 = m (x - x_1)   Plug in either set of coordinate. I chose (3, 18).
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  y - 18 = 6x - 18         Add 18 to both sides
        y = 6x

The equation of a direct variation line that includes the point (3, 18) is y = 6x.
  
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