Ask question

Ask question

All categories

2 years ago

10

Sarah was walking and picked up a rock that she thought looked interesting. The rock appeared to have layering, and contain frag

ments of shells and bones. What is the correct classification of the rock Sarah picked up?
Igneous
Metamorphic
Sedimentary
Volcanic

1 answer:

vladimir2022 [97]2 years ago

5 0

The answer would be ~sedimentary~

Hope this helps

Have a great day/night

You might be interested in

What is the formula for the compound formed by lead(II) ions and Chlorine ions?

Olenka [21]

Answer:

Pb(CrO4)Al2(SO4)3

Explanation:

3 0

3 years ago

Of the elements: b, c, f, li, and na. the element with the highest ionization energy is

padilas [110]

Carbon has the highest ionization energy as its energy 1086KJ\Mol and the rest are between 500 and 800.

6 0

3 years ago

Which of these is found in the energy levels of an atom?

Paul [167]

Answer:

Electrons

Explanation:

Because the nucleas is In the middle and the Electrons surround it

3 0

2 years ago

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

Which way would CCI2F2 orient in an electric field?

ArbitrLikvidat [17]

Answer:

See explanation

Explanation:

In looking at molecules to determine whether they are polar or not we have to look at two things basically;

i) presence of polar bonds

ii) geometry of the molecule

Now, we know that CCI2F2 is a tetrahedral molecule, but the molecule is not symmetrical. It has four polar bonds that are not all the same hence the molecule is polar.

In an electric field, polar molecules orient themselves in such a way that the positive ends of the molecule are being attracted to the negative plate while the negative ends of the molecules are attracted to the positive plate.

So the positive ends of CCI2F2 are oriented towards the negative plate of the field while the negative ends of CCI2F2 are oriented towards the positive ends of the field.

3 0

2 years ago