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NISA [10]
3 years ago
8

Four forces are acting on an object one force is pulling two Newtons to the left the second force is pulling 2 Newton’s up the t

hird is pulling three newton’s down and the last is pulling two newtons to the right what is the size and direction of the net force
Physics
1 answer:
Sedaia [141]3 years ago
7 0

Answer:

Explanation:

1. The net force acting on an object is the combination of all of the individual forces acting on it.

2. If two forces act on an object in opposite directions, the net force is the difference between the two forces.

3. If two forces act on an object in the same direction, the net force is the sum of the two forces.

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A rock from Mars experiences a 263% increase in its weight once it arrives on Earth. What accounts for this increase in weight?
leva [86]
The mass of Mars is smaller than that the mass of Earth, therefore the acceleration of gravity on Mars is much less than that the acceleration of gravity of the Earth.

 The weight of an object is directly proportional to the magnitude of the gravitational acceleration of the planet where it is.

 In this case, the gravitational acceleration in Mars is 3.711 m/s² and that of the planet Earth is 9.807 m/s².

 The acceleration of gravity on Earth is 2.63 times greater than that the acceleration of gravity on Mars. This explains that the same object weighs 263% more on earth
3 0
3 years ago
FILL IN THE BLANK. immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called th
Marrrta [24]

Immediately following the arrival of the stimulus at a skeletal muscle cell, there is a short period called the latent period during which the events of excitation-contraction coupling occur.

This process is a connection between transduction in the sarcolemma and the initiation of muscle contraction. Sarcolemma is nothing but the cell membrane of skeletal muscle.

A single muscle twitch has a latent period, a contraction phase when tension increases and a relaxation phase when tension decreases.

The period of incubation, the interval preceding exposure to a pathogen toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus and muscle contraction.

To know more about muscles:

brainly.com/question/13753345

#SPJ4

6 0
1 year ago
How to start my introduction in science about the history of matter?
postnew [5]
Start with an anecdote, surprising fact or quotes
5 0
3 years ago
An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
Marysya12 [62]

When air is blown into the open pipe,

L = \frac{nλ}{2}

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=\frac{2L} {n}

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ=\frac{(2)*(6)}{4} =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f= \frac{c}{λ}

⇒f=\frac{344}{3}

≈115 Hz

8 0
4 years ago
Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of
Alchen [17]

Answer:

\theta=10.20^{\circ}  

\Delta l=0.10 ft    

Explanation:

First of all, we analyze the system of blocks before starting to move.

\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0  

\Sum F_{x}=11sin(\theta)+5sin(\theta)-0.16N_{A}-0.23N_{B}=0

11sin(\theta)+5sin(\theta)-0.16P_{A}cos(\theta)-0.23P_{B}cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0

11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0  

16sin(\theta)-2.91cos(\theta)=0  

tan(\theta)=0.18  

\theta=arctan(0.18)  

\theta=10.20^{\circ}  

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.  

P_{A}sin(\theta)-F_{fA}-F_{spring}=0

Where:

F_{spring} = k\Delta l=2.1\Delta l

P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0

\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}

\Delta l=0.10 ft    

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

4 0
4 years ago
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