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vlabodo [156]
2 years ago
15

Air near Earth's surface rises up into the atmosphere as it is heated by _____.

Physics
2 answers:
cricket20 [7]2 years ago
8 0
<span>Air near Earth's surface rises up into the atmosphere as it is heated by "The Wind"

Hope this helps!</span>
chubhunter [2.5K]2 years ago
4 0

Answer:

a. the wind

Explanation:

Air near Earth's surface rises up into the atmosphere as it is heated by the wind.  Then, convection transfers heat energy from warmer regions near the Earth's surface to regions higher up in the atmosphere, that happen because warmer air has a lower density than cold air

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What is 2,000m to km​
lesantik [10]

Answer: 2km

Explanation:

7 0
3 years ago
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An electron initially has a speed 16 km/s along the x-direction and enters an electric field of strength 27 mV/m that points in
weqwewe [10]

Answer:

a)t=1.4\times 10^{-5}\ s

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

E= 27 mV/m

E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

t=1.4\times 10^{-5}\ s

b)

We know that

F = m a = E q                    ------------1

Mass of electron ,m

m=9.1\times 10^{-31}\ kg

Charge on electron

q=1.6\times 10^{-19}\ C

So now by putting the values in equation 1

a=\dfrac{E q}{m}

a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2

a=4.74\times 10^{9}\ m/s^2

S= ut+\dfrac{1}{2}at^2

Here initial velocity u= 0 m/s

S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

4 0
3 years ago
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How much work is done when a 214 newton force pushes a sleeping cow 37m across a field.
nata0808 [166]
Hello!

Answer: 
7918 J

Explanation:

We are assuming that the floor (field) is completely horizontal since there's no information about that in the statement. 

We are going to use the following formula:

W= F . Cos \alpha . D

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Then, by substituting we have:

W=214N . Cos (0).37m= 7918 N.m=7918 J

8 0
3 years ago
You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the
podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

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F_y = Fsin30


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N = Fsin30 + mg

N = 0.5F + (18\times 9.8)

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now the friction force on the cart is given as

F_f = \mu N

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F_f = 110.25 + 0.3125F

now if cart moves with constant speed then net force on cart must be zero

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0.866F - 0.3125F = 110.25

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8 0
3 years ago
If the wagon travels 18.75 m, what is the work done on the wagon
Schach [20]

If the wagon travels 18.75 m, then the work done on the wagon is

(18.75 m) x (the steady force applied to the wagon all the way, in Newtons) .

The unit is Joules .


4 0
3 years ago
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