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3 years ago

13

Suppose a current flows through a copper wire. Which two things occur?

1 answer:

Bingel [31]3 years ago

4 0

Answer:

a

Explanation:

as the copper wire is very dangerous so now if these two thing happens then it would easily help the current flows through it so it might be a little bit easy for the current to flow through it

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An airplane flies due north at 225 km/h relative to the air. There is a wind blowing at 60 km/h to the northeast relative to the

miv72 [106K]

Answer:

270.78 m/s and 9 degrees north of east

Explanation:

Suppose that the wind direction is 45 degree relative to the eastern direction. Let east and north be the positive horizontal ( $\hat{i}$ ) and vertical ( $\hat{j}$ ) directions here. We can calculate the horizontal and vertical components of wind velocity

$v_v = v_h = 60 cos45^0 = 60*0.707 = 42.43 km/h$

The velocity of the wind can be rewritten as the following

$\vec{v_w} = 42.43 \hat{i} + 42.43 \hat{j}$

The velocity of the airplane that is 225 km/h due north is

$\vec{v_a} = 225 \hat{j}$

The plane velocity relative to the ground is its velocity relative to the wind plus the wind velocity relative to the ground

$\vec{v} = \vec{v_w} + \vec{v_a} = 42.43 \hat{i} + 42.43 \hat{j} + 225 \hat{j} = 42.43 \hat{i} + 267.43 \hat{j}$

The magnitude and direction of this velocity vector can be calculated

$v = \sqrt{v_x^2 + v_y^2} = \sqrt{42.43^2 + 267.43^2} = \sqrt{1800.3049 + 71518.8049} = \sqrt{73319.1098} = 270.78$

$tan\alpha = \frac{v_x}{v_y} = \frac{42.43}{267.43} = 0.16$

$\alpha = tan^{-1}0.16 = 0.16 rad \approx 9.02 degrees$ north of east

7 0

3 years ago

Where is the Ring Of Fire located?

Bingel [31]

Answer:

The pacific ocean

Explanation:

because the pacific ocean is where many earthquakes and volcanic eruptions occur.

8 0

3 years ago

Read 2 more answers

One molecule of glucose makes 30 molecules of atp. how many molecules of glucose are needed to make 300 molecules of atp in aero

leonid [27]

10 molecules are required

8 0

4 years ago

Read 2 more answers

Represent the following sentence as an algebraic expression, where "a number" is the

agasfer [191]

Answer:

2 (x+3)

Explanation:

8 0

3 years ago

A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.4 ft/s,

Art [367]

Answer:

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

Explanation:

given,

length of ladder = 10 ft

let x be the distance of the bottom and y be the distance of the top of ladder.

x² + y² = 100

differentiating with respect to time we get

$2 x\dfrac{dx}{dt}+2y\dfrac{dy}{dt} = 0$ ..............(1)

when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s

from equation (1)

now,

$16\times 1.4 + 12\dfrac{dy}{dt} = 0$

$\dfrac{dy}{dt} = -\dfrac{5.6}{3}$

let the angle between the ladders be θ

$tan\theta = \dfrac{y}{x}$

y = xtan θ

$\dfrac{dy}{dt} =\dfrac{dy}{dt} tan\theta + x sec^2\theta\dfrac{d\theta}{dt}$

$-\dfrac{5.6}{3} =1.4\times \dfrac{6}{8} + 8 (1+\dfrac{9}{16})\dfrac{d\theta}{dt}$

$\dfrac{25}{2} \dfrac{d\theta}{dt} =\dfrac{-17.5}{6}$

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

6 0

3 years ago