I would say because they have the same negative charge and they repel each other
As it is given to us
also it is given that
P - Q + R = 0
so here we can rearrange it to find the value of R
so here we have
so the vector is given by above equation
You have a point on a rectangular graph with coordinates (6, 8).
You want to describe the same location in polar coordinates ... R and Θ .
-- 'R' is the distance from the origin to the point.
-- 'Θ' is the angle you'd need to turn the x-axis counterclockwise
around the origin to make it pass through the point.
To change rectangular coordinates to polar coordinates:
R = √(x² + y²)
Θ = the angle whose tangent is (y / x) .
(6i + 8j) is the [Cartesian] vector that takes you from the origin to (6, 8) .
R = √(6² + 8²) = √(36 + 64) = √100 = 10
Θ = tan⁻¹ (8/6) = 53.13° (rounded)
In polar coordinates, the same point is 10 ∠53.13° .
Answer:
The drawing of the free body diagram is in the attachment.
Explanation:
In order to draw a<em> free body diagram</em>, you have to include in the drawing all the acting forces in the box for the given situation.
The acting forces are:
-The normal force (N), which is the contact force that the inclined plane applies to the box. This force is perpendicular to the contact surface.
-The weight force (W), which is due to the force of gravity on the box. The direction of the weight force is vertical (perpendicular to the ground)
-The friction force (Fs), which in this case is the static friction force because the box is in rest. The direction of this force is opposite to the direction of the movement.
Therefore, you have to draw the inclined plane, the box and the acting forces (See the attachment)
coefficient of static friction is 1.7329
Explanation:
given data
velocity = 60 mph
acceleration = 17 m/s²
to find out
coefficient of static friction
solution
we will apply here centripetal force equation
that is
m×v²/r = µ × m × g ..................1
here v²/r is centripetal acceleration and m is mass and µ is coefficient static friction so
µ = a / g
µ = 17 / 9.81
µ = 1.7329
so coefficient of static friction is 1.7329