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ohaa [14]
3 years ago
12

Pls help ASAP due tonight

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Y= -1/3x +5

5 is the y-intercept (where the line touches the y-axis) and -1/3 is the slope (rise over run, but since its negative, you go down 1, over 3 to the right) Hope this helps!!!

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Find the equation of the straight line through (–2, 3) perpendicular<br> to 2x + y =8
Thepotemich [5.8K]

Answer:

y = \dfrac{1}{2}x + 4

Step-by-step explanation:

The equation of a line in slope-intercept form is

y = mx + b

We need to find the slope, m, and the y-intercept, b.

The line we need is perpendicular to the line 2x + y = 8.

<em>The slopes of perpendicular lines are negative reciprocals.</em>

We solve the given equation for y to find the slope of the given line.

2x + y = 8

y = -2x + 8

The given line has slope -2.

The negative reciprocal of -2 is 1/2.

Our line has slope, m = 1/2.

Now we have

y = 1/2 x + b

Now we use the given point, (-2, 3), for x and y, using x = -2, and y = 3, and we solve for b.

y = 1/2 x + b

3 = 1/2 * (-2) + b

3 = -1 + b

4 = b

b = 4

Now we have

y = 1/2 x + 4

Answer: y = \dfrac{1}{2}x + 4

8 0
3 years ago
Find the distance between the points (-5, -10) and (2, 4).
Basile [38]

i am certain that this is the answer

4 0
3 years ago
Read 2 more answers
Reggie Means invested part of $31,000 in municipal bonds that earn 7.5% annual simple interest and the remainder of the money in
insens350 [35]

Answer:

Principal Invested in Municipal Bonds is $16,000

Principal Invested in Corporate Bonds is $15,000

Step-by-step explanation:

If;

Principal Invested in municipal bonds = a

Principal Invested in corporate bonds = b

then we have;

a + b = $31,000 --------------------------------Equation 1

0.075a + 0.085b = $2,475  ---------------Equation 2

From equation 1 we have;

a = 31,000 - b

By putting the values of a in Equation 2 we get;

0.075 (31,000 - b) + 0.085b = 2,475

2,325 - 0.075b + 0.085b = 2,475

0.01b = 150

b = $15,000

By putting the values of b in equation 1 we get;

a = $16,000

4 0
3 years ago
A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
Of 125 students in 5th grade, 3/5 of them have a mobile phone. How many students do not have a mobile phone?
Annette [7]

Answer:75

Step-by-step explanation:125÷ 5=25

25*3=75

5 0
4 years ago
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