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yKpoI14uk [10]
3 years ago
14

How many particles are in 54.5 g of aluminum? Show your work.

Chemistry
1 answer:
Ludmilka [50]3 years ago
7 0
There are 1.216x10^24 particles in 54.5g of aluminum.

A. 54.5/26.98 = 2.02mols of aluminum

B. 2.02mols*6.02x10^23 particles/mol = 1.216x10^24
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Water molecules are positive on one end, negative on the other. Predict what a negatively charged balloon will do when placed cl
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7 0
2 years ago
How do you find the # of sigma and pi bonds using a Lewis dot structure
Lubov Fominskaja [6]

Every single bond is a sigma bond.

A double bond contains 1 sigma bond and 1 pi bond.

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3 0
3 years ago
2zn+o2=2zno <br><br> how many moles of zinc are needed to make 6 moles of zinc oxide?
Temka [501]

Answer:

\boxed{\text{6 mol}}

Explanation:

(a) Balanced equation

2Zn + O₂ ⟶ 2ZnO

(b). Calculation

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The molar ratio is 2 mol Zn:2 mol ZnO

\text{Moles of Zn} =\text{6 mol ZnO} \times \dfrac{\text{2 mol Zn}}{\text{2 mol ZnO}} = \text{6 mol Zn}\\\\\text{You need }\boxed{\textbf{6 mol of Zn}}\text{ to form 6 mol of ZnO}.

3 0
3 years ago
A salt is known to be an alkali metal fluoride. A quick approximate determination of freezing point indicates that 4 g of the sa
nexus9112 [7]
For the answer to the question above, I can't help you directly because I don't have a calculator right now. But I'll show you how to solve this.
<span>use the freezing point depression formula for this one: delta T = i * m * K where K is a constant, m is the molality (mol solute/kg solvent), and i is the van'hoff factor the van hoff factor is the number of ions that your salt dissociates into. Since it's an ALKALI flouride salt, how many ions? k is just a constant, you get it from a table in your textbook somewhere So you have everything to solve for the molality of the solution, once you did that, multiplying it by the mass of water to find the mols of the salt. Take the mass of the salt and divide by this mols to figure out the molar mass, and then compare it with the periodic table to identify the salt.
</span>
<u>Mole solute</u>   x  mass of Water  = Mol solute<u>
</u>kg Solvent

then 

Mass of solute  x  <u>            1             </u>   =  molar mass
                               mole of solute

4 0
3 years ago
Read 2 more answers
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