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2 years ago

Victor bought a new soccer ball. The original price was $29.99, but the ball was on sale for 15% off. What was the sale price?

Mathematics

1 answer:

Inessa [10]2 years ago

4 0

Answer:

Sale price= $25.5

Step-by-step explanation:

Giving the following information:

The original price was $29.99, but the ball was on sale for 15% off.

To calculate the sales price, we need to use the following formula:

Sale price= original price* (1 - sales discount)

Sale price= 29.99*(1 - 0.15)

Sale price= $25.5

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In a candy box, there are 5 times as many candies with nuts as candies without nuts. There are 30 candies in the box. How many c

Luden [163]

Answer:

Step-by-step explanation:

because there are 5 time as many candies with nuts as candies without nuts and there is 18 so it will be 18×5=90

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2 years ago

Find the value of x in the triangle.

Studentka2010 [4]

Answer:

164

Step-by-step explanation:

Remember, everytriangle is 180 all together. So add what you see and subtract it from 180.

9+7= 16

180-16= 164

Hope it helps

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2 years ago

28 is what percent of 50?

nikdorinn [45]

Answer:

go to 100

56 is 56 percent of 100

28 is 56 percent of 50

Step-by-step explanation:

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2 years ago

A number y multiplied by −3 is less than −2/5. Write this word sentence as an inequality.

bazaltina [42]

The answer is -3y < -2/5

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3 years ago

Evaluate the difference quotient for the given function. Simplify your answer.

nasty-shy [4]

I suppose you mean

$f(x) = \dfrac{x+5}{x+1}$

Then

$f(3) = \dfrac{3+5}{3+1} = \dfrac84 = 2$

and the difference quotient is

$\dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5}{x+1}-2}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{\frac{x+5-2(x+1)}{x+1}}{x-3} \\\\ \dfrac{f(x)-f(3)}{x-3} = \dfrac{-x+3}{(x+1)(x-3)} \\\\ \dfrac{f(x)-f(3)}{x-3} = \boxed{-\dfrac{x-3}{(x+1)(x-3)}}$

If it's the case that x ≠ 3, then (x - 3)/(x - 3) reduces to 1, and you would be left with

$\dfrac{f(x)-f(3)}{x-3}\bigg|_{x\neq3} = -\dfrac1{x+1}$

4 0

2 years ago