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Alexandra [31]
4 years ago
15

Identify the frequency used by these broadcast media. FM AM Television

Physics
2 answers:
Oliga [24]4 years ago
7 0

Answer:

AM radio = 540 - 1650 KHz

FM radio = 88 to 108 MHz

Television = 54 to 216 MHz

Lapatulllka [165]4 years ago
4 0

Answer:

FM:Very High Frequency

AM:Low Frequency

Television: Very High Frequency

Explanation:

Edge 2020

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What other angle would give the same range at 19 degrees?
yaroslaw [1]

Answer:

I think it is acute angle.

Explanation:

Because it is an angle between 0° and 90°. Hope this answer wil help you.

8 0
3 years ago
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An object traveling at a 5.0 m/s East has a mass of 4.0 kg. What is the magnitude of the object’s momentum?
DaniilM [7]

Answer:

20 kgm/s

Explanation:

Momentum=mass * velocity

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6 0
4 years ago
A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa
Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute =W_B=10 g

Given mass of solvent=W_A=90 g

k_f=1.86^{\circ}C/m

Freezing point of solution =-3.33^{\circ}C

Freezing point of solvent =0^{\circ}C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33=3.33^{\circ}

\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}

M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}

M_B=62.06 g/mol

Hence, molar mass of unknown liquid is 62.06g/mol.

6 0
3 years ago
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If a car starts from rest and accelerates at 4 m/s2 for 8 sec, how far did it travel and how fast was it moving at the end of th
butalik [34]

Answer:did you ever get the answer?

Explanation:

3 0
3 years ago
The first law of thermodynamics states that the change U in the internal energy of a system is given by U Q W, where Q is the he
lilavasa [31]

Answer:

d

Explanation:

First law of thermodynamics

 It is also known as energy conservation law.It state that net work in a cyclic process is equal to net heat in that cycle.

From first law

Q=ΔU + W

ΔU = Q - W

ΔU is the change in internal energy of gas.

Q is heat transfer from the system or to the system.

W is the work done by the system or on the system.

If work done on the system then it will be taken as positive and If work done by the system then it will be taken as negative.

If heat taken by system it will taken as positive and If heat rejected by system it will taken as negative.

So Q will be positive if system gains heat and work will be positive if work is done on the system.

4 0
3 years ago
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