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kramer
3 years ago
6

A 7.0kg object rests on a horizontal frictionless surface. What is the magnitude of the horizontal

Physics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

16.1 N

Explanation:

From the question,

F = ma.............................. Equation 1

Where F = horizontal force, m = mass of the object, a = acceleration .

Given: m = 7.0 kg, a = 2.3 m/s²

Substitute this values into equation 1

F = (7.0×2.3)

F = 16.1 N.

Hence the magnitude of the horizontal force is 16.1 N

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What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?
MA_775_DIABLO [31]

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

7 0
2 years ago
The literary movement with which Wilde is most closely associated is Select one: a. romanticism b. existentialism c. Art for art
jeyben [28]

Answer:

Correct answer is ''c'' Art for art's Sake

Explanation:

Wilde wrote in the literary movement called Aestheticism during the late nineteenth century. Contrary to popular belief, Wilde did not create the literary movement, but played a role as a leader who promoted the movement. While Wilde was a college student the works of Algernon Charles Swinburne and Edgar Allan Poe influenced his own writing style. Also, the English essayist Walter Pater helped to form Wilde's humanistic aesthetics.

The philosophical foundations of Aestheticism come from Immanuel Kant. He formulated the idea of "art for art's sake". He believed that art was to be enjoyed for its own beauty regardless of social or moral concerns.

6 0
3 years ago
A 1,70 atm, una muestra de gas ocupa 4,25 litros. Si la presión en el gas aumenta a 2.40 atm, ¿cuál será el nuevo volumen?
statuscvo [17]

At 1.70 atm, a gas sample occupies 4.25 liters. If the pressure in the gas increases to 2.40 atm, what will the new volume be?

Answer:

3.01L

Explanation:

Given parameters:

Initial pressure, P1  = 1.7atm

Initial volume, V1  = 4.25L

Final pressure, P2  = 2.4atm

Unknown:

Final or new volume, V2  = ?

Solution:

To solve this problem, we use Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes, if the temperature is constant".

            P1 V1  = P2 V2

P1 is the initial pressure

V1 is the initial volume

P2 final pressure

V2 final volume

        1.7 x 4.25  = 2.4 x V2

             V2  = 3.01L

8 0
4 years ago
A)If the rms value of the electric field in an electromagnetic wave is doubled, by what factor does the rms value of the magneti
Ghella [55]

A) The magnetic field doubles as well

The relationship between rms value of the electric field and rms value of the magnetic field for an electromagnetic wave is the following:

E_{rms}=cB_{rms}

where

E_rms is the magnitude of the electric field

c is the speed of light

B_rms is the magnitude of the magnetic field

From the equation, we see that the electric field and the magnetic field are directly proportional: therefore, if the rms value of the electric field is doubled, then the rms value of the magnetic field will double as well.

B) The intensity will quadruple

The intensity of an electromagnetic wave is given by

I=\frac{1}{2}c\epsilon_0 E_0^2

where

c is the speed of light

\epsilon_0 is the vacuum permittivity

E_0 is the peak intensity of the electric field

The rms value of the electric field is related to the peak value by

E_{rms}=\frac{E_0}{\sqrt{2}}

So we can rewrite the equation for the intensity as

I=c\epsilon_0 E_{rms}^2

we see that the intensity is proportional to the square of the rms value of the electric field: therefore, if the rms value of the electric field is doubled, the average intensity of the wave will quadruple.

7 0
3 years ago
2. A rock is dropped from rest at the top of a 10 meter tall building. How much time does the rock
ivann1987 [24]

Answer:

1.4 seconds

Explanation:

here u= 0

v= ?

h= 10m

g= 9.8 m/ s*2

using 2as = v^2 - u ^2

2x9.8x10 = v^2 - 0

v^2 = 196

v = 14 m

time = v- u/ a

14 / 98

1.4 seconds

7 0
3 years ago
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