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3 years ago

6

Rank the following compounds in order of decreasing vapor pressure.

1 answer:

AleksandrR [38]3 years ago

3 0

The pursuit of that answer would be a pleasant exercise if you had
listed any items to be ranked. Sadly, you didn't.

It's a lot like saying "Arrange these people in order of their ages", and
then not telling us how old any of them are.

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24. Most cleaning solutions like soap, with a pH of 8-9 are examples of a(n)

Sphinxa [80]

24. A, natural ph scale for it not to be acidic is 7-8

25. A, not sure about this one

26. A, looked it up

27. A, because it has to be shaken up to make the mixture appear and taste more combined.

28. D, i just guessed

29. D, that answer is stupid so it is the answer because it said not a property

30. A, looked it up

8 0

4 years ago

Someone please help !!

rodikova [14]

What is the Investigation about!

5 0

3 years ago

A wave has a wavelength of 7 mm and a frequency of 19 hertz. What is its speed?

ASHA 777 [7]

Speed = (frequency) x (wavelength)

Speed = (19 per second) x (7 mm)

Speed = (19 x 7) (per second · mm)

<em>Speed = 133 mm/sec</em>

or you might want to write <em>Speed = 0.133 m/s</em> .

4 0

4 years ago

What force is needed to move a barrel 45-m if 3600 J of work are accomplished?

lesantik [10]

Answer:

<h3>The answer is 80 N</h3>

Explanation:

The force acting on the object can be found by using the formula

$f = \frac{w}{d} \\$

where

d is the distance

w is the work done

We have

$f = \frac{3600}{45} \\$

We have the final answer as

<h3>80 N</h3>

Hope this helps you

8 0

3 years ago

An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I

oksano4ka [1.4K]

Answer:

The deviation in path is $4.39 \times 10^{-3}$

Explanation:

Given:

Velocity $v = 1 \times 10^{6}$ $\frac{m}{s}$

Electric field $E = 500$ $\frac{V}{m}$

Distance $x = 1 \times 10^{-2}$ m

Mass of electron $m = 9.1 \times 10^{-31}$ kg

Charge of electron $q = 1.6 \times 10^{-19}$ C

Time taken to travel distance,

$t = \frac{x}{v}$

$t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }$

$t = 10^{-8}$ sec

Acceleration is given by,

$F = qE$

$ma = qE$

$a = \frac{qE}{m}$

$a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }$

$a = 8.77 \times 10^{13}$ $\frac{m}{s^{2} }$

For finding the distance, we use kinematics equations.

$y = vt + \frac{1}{2} at^{2}$

Where $v = 0$ because here initial velocity zero

$y = \frac{1}{2} at^{2}$

$y = \frac{1}{2} \times 8.77 \times 10^{13 } \times (10^{-2} )^{2}$

$y = 4.39 \times 10^{-3}$ m

Therefore, the deviation in path is $4.39 \times 10^{-3}$

6 0

3 years ago