Answer:
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Explanation:
Propane can be turned into hydrogen by the two-step reforming process.
In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:
C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)
In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:
CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)
In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.
C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)
C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)
Answer:
0.702M
Explanation:
Molarity of a solution, which refers to the molar concentration of that solution can be calculated thus;
Molarity = number of moles (n) ÷ volume (V)
Firstly, we convert 18.5 grams of NaCl to moles using the formula; mole = mass/molar mass
molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 18.5/58.5
mole = 0.32moles
Volume of water (V) = 450mL = 450/1000 = 0.450L
Molarity = n/V
Molarity = 0.32/0.450
Molarity = 0.702M
<h3><u>Answer;</u></h3>
<u>= 128.772 g of water</u>
2C6H14 + 13 O2 → 6CO2 + 14 H2O
<h3><u>Explanation</u>;</h3>
1 mole of Hexane contains 86 g
Therefore;
87.91 grams of hexane will contain
= 87.91 g/86 g
= 1.022 moles
The balanced reaction for the combustion of Hexane is given by
2C6H14 + 13 O2 → 6CO2 + 14 H2O
Therefore; the mole ratio of C6H14 :H2O is
= 2 : 14
= 1: 7
therefore moles of water from 1.022 moles of Hexane will be;
= 1.022 ×7
= 7.154 moles
Mass of water will be;
= 7.154 moles× 18
<u>= 128.772 g of water</u>
Answer:
Explanation:
Toe change the retention factor of a TLC analysis, you can change your solvent for a more or less polar one, depending on your analyte. You can use a mix of solvents too.
You can also change the your method to visualize the spots, you can use fluorescent compounds that can only be seen in black light, you can use Iodine, Bromine and so on.
When the overall charge is equal to zero
