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ElenaW [278]
3 years ago
6

Help!! 10 points!! Please don’t answer if u don’t know!!

Chemistry
2 answers:
jek_recluse [69]3 years ago
6 0

Answer:

the answer is A a new substance is formed

melomori [17]3 years ago
3 0

Answer:

A. A new substance is formed

Explanation:

The mixture quickly foams up with carbon dioxide gas which then if enough vinegar is used, all of the baking soda can be made to react and disappear into the vinegar solution...

Hope it helped

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List 4 things that could happen to the water used in watering local golf course
Advocard [28]
The water used to water a golf course may be:
1) Carried off the surface of the golf course into nearby streams or rivers
2) Evaporated
3) Lost to the ground by the process of leaching
4) Absorbed by the vegetation in the golf course such as the grass, trees and shrubs.
3 0
4 years ago
Determine the maximum amount of NaNO3 that was produced during the experiment. Explain how you determine this amount.
Natali5045456 [20]

Answer:

9 moles

Explanation:

see image linked!

8 0
2 years ago
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What type of compound is CH3―O―CH2―CH2―CH3?
Lelu [443]
Ether

methoxypropane (methyl propyl ether)
5 0
4 years ago
31.5 grams of an unknown substance is heated to 102.4 degrees Celsius and then placed into a calorimeter containing 103.5 grams
Alexxandr [17]
Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:<span>

Heat = mC(T2-T1) 

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

</span>Heat gained = Heat lost
mC(T2-T1) = - mC(T2-T1) 
31.5C (102.4 - 32.5) = 103.5(4.18)(32.5 - 24.5)
C = 1.57 J/C-g

Hope this helps.
5 0
3 years ago
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
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