All categories

3 years ago

Help!! 10 points!! Please don’t answer if u don’t know!!

Chemistry

2 answers:

jek_recluse [69]3 years ago

6 0

Answer:

the answer is A a new substance is formed

melomori [17]3 years ago

3 0

Answer:

A. A new substance is formed

Explanation:

The mixture quickly foams up with carbon dioxide gas which then if enough vinegar is used, all of the baking soda can be made to react and disappear into the vinegar solution...

Hope it helped

You might be interested in

Write the balanced chemical equation for the reaction of potassium metal (k) with water to yield potassium hydroxide.

Tanzania [10]

Reaction: 2K₍s₎ + 2H₂O₍l₎ → 2KOH₍aq₎ + H₂₍g₎.
K - potassium.
H₂O - water.
KOH - potassium-hydroxide.
H₂ - hydrogen.
s - solid phase.
l - liquid.
aq - disolves in water.
g - gas.
Reaction is exothermal (release of energy) and potassium burns a purple flame. Hydrogen released during the reaction reacts with oxygen and ignites.

7 0

3 years ago

Describe the difference between a reaction that occurs spontaneously and one that does not

lidiya [134]

2.B. Describe the difference between a reaction that occurs spontaneously and one that does not. Spontaneous chemical reactions release energy and use that energy to power itself; non-spontaneous chemical reactions need to absorb energy, which they can't absorb their own energy that they don't even have.

4 0

3 years ago

For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula

Dafna11 [192]

$\\ \sf\longmapsto FeP$

$\\ \sf\longmapsto Fe_2S_3$

$\\ \sf\longmapsto FeCl_2$

$\\ \sf\longmapsto MgCl_2$

$\\ \sf\longmapsto MgO$

$\\ \sf\longmapsto Mg_3N_2$

$\\ \sf\longmapsto Na_3P$

$\\ \sf\longmapsto Na_2S$

$\\ \sf\longmapsto CoO$

$\\ \sf\longmapsto Co_2S_3$

$\\ \sf\longmapsto AlCl_3$

$\\ \sf\longmapsto CsBr$

$\\ \sf\longmapsto Ti_2O_4$

$\\ \sf\longmapsto Ag_2S$

4 0

3 years ago

Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho

Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

$2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\$

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

$n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2$

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

$m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3$

c) The leftover is computed as follows:

$m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\$

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0

3 years ago

I need help what is s-1/3=7/9???? please help guys and thank you

nalin [4]

Answer:

10/9

Explanation:

First, let's convert 1/3 and 7/9 so that the have the same denominator. To do this let's find the least common multiple of 3 and 9.

List the multiples of 3 and 9:

3: 3, 9

9: 9

They have a least common multiple of 9

We need to convert 1/3 so it has a denominator of 9:

1/3*3/3 (we can multiply it by 3/3 because any number over itself is 1) = 3/9

s-3/9=7/9

Add 3/9 to both sides to isolate s

s=10/9

6 0

3 years ago