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Sever21 [200]
3 years ago
8

Can someone give me an example of balancing equations with a solution that is simple?​

Chemistry
2 answers:
Monica [59]3 years ago
6 0

Explanation:

H _{2}O _{2(aq)} →H _{2}O _{(l)}  + O _{2}(g) \\ solution  : 2 \:  and\: 2

avanturin [10]3 years ago
6 0
Here is an example
The equation:
K + HOH -> KOH + H2 (an example of a single replacement reaction)
Balanced equation:
2 K + 2 HOH -> 2 KOH + 1 H2
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How much energy is needed to warm 7.40g of water by 55 degress C?
zloy xaker [14]
<span>E = mCdT
E = energy, m = mass, C = specific heat capacity, dT = change in temperature.
526 = 0.074C x 17
E = 0.074C x 55
Divide the equations
E/526 = (0.074C x 55)/(0.074C x 17) = 55/17
E = (55 x 526)/17 = 1702 J</span>
8 0
3 years ago
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5 0
3 years ago
What is the molality of a solution containing 2.6 moles of sugar and 6 kg water?
Pachacha [2.7K]

Convert kg into L, then take the moles and divide it by the L of water

8 0
3 years ago
Read 2 more answers
mixture or pure substance: 1.blood 2.dyes 3.self-raising flour 4.muesli 5.copper wire 6.distilled water 7.table salt 8.milk 9.br
jenyasd209 [6]

Answer: Mixture: Blood , Self raising flour,muesli ,dyes, milk, tea, air, bronze

Pure substance: Copper wire, distilled water, table salt, oxygen.

Explanation:

Mixture is a substance which is made up two or more number of compounds which chemically inactive and retain their distinct chemical properties.

Blood , Self raising flour,muesli ,dyes, milk, tea, air, bronze

Pure substance is defined as anything with uniform and unchanging composition is known s pure substance.

Copper wire, distilled water, table salt, oxygen.

5 0
3 years ago
A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your
amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically,         Molarity = \frac{\text{no. of moles}}{\text{Volume in liter}}

Also, when number of moles are equal in a solution then the formula will be as follows.

                     M_{1} \times V_{1} = M_{2} \times V_{2}

It is given that M_{1} is 8.00 M, V_{1} is 7.00 mL, and M_{2} is 0.80 M.

Hence, calculate the value of V_{2} using above formula as follows.

                    M_{1} \times V_{1} = M_{2} \times V_{2}

                 8.00 M \times 7.00 mL = 0.80 M \times V_{2}

                      V_{2} = \frac{56 M. mL}{0.80 M}

                                  = 70 ml

Thus, we can conclude that the volume after dilution is 70 ml.

7 0
3 years ago
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